Python：每日一题 24（答题领鱼币）

pillar

学以一波

yang_zhong_well

用的笨方法，验证过，没问题

1. def is_leap_year(year):
   
2.     if year%400 == 0 or (year%4 ==0 and year%100!=0):
   
3.         return True
   
4.     else:
   
5.         return False
   
6. 
   
7. def num_daysOfmonth(year,month):
   
8.     l1=[1,3,5,7,8,10,12]
   
9.     if month in l1:
   
10.         return 31
    
11.     else:
    
12.         if month == 2:
    
13.             if is_leap_year(year):
    
14.                 return 29
    
15.             else:
    
16.                 return 28
    
17.         else:return 30
    
18. 
    
19. def days_ruzhi():
    
20.     currentDate = raw_input("请输入今天的日期（eg：2017-11-13）：")
    
21.     ruzhiDate = '2014-8-18'
    
22.     curList = currentDate.split('-')
    
23.     ruzhiList = ruzhiDate.split('-')
    
24.     curList = map(int,curList) #将一个list元素转变为整型
    
25.     ruzhiList = map(int,ruzhiList)
    
26. 
    
27.     total_days = 0
    
28.     #print curList,ruzhiList
    
29.     #当前日期和入职日期在同一年
    
30.     if curList[0] - ruzhiList[0] == 0:
    
31.         if curList[1] - ruzhiList[1] == 0:
    
32.             total_days = curList[2] - ruzhiList[2] + 1
    
33.         else:
    
34.             for month in range(ruzhiList[1], curList[1]):
    
35.                 if month > curList[1]:
    
36.                     total_days += num_daysOfmonth(ruzhiList[0], month)
    
37.                 else:total_days += num_daysOfmonth(ruzhiList[0], month) - ruzhiList[2] + 1
    
38.             total_days += curList[2]
    
39.         print "您好，今天是您入职第%d天"%total_days
    
40.         sys.exit(0)
    
41.     #入职第三年及以后
    
42.     if curList[0] - ruzhiList[0] > 1:
    
43.         for year in range(ruzhiList[0]+1,curList[0]):
    
44.                 if is_leap_year(year):
    
45.                     total_days += 366
    
46.                 else:total_days += 365
    
47.                 print "test1:", total_days
    
48. 
    
49.     #入职=1年
    
50.     for month_ruzhi in range(ruzhiList[1], 13):
    
51.         if month_ruzhi > ruzhiList[1]:
    
52.             total_days += num_daysOfmonth(ruzhiList[0], month_ruzhi)
    
53.         else:
    
54.             total_days += num_daysOfmonth(ruzhiList[0], month_ruzhi) - ruzhiList[2] + 1
    
55.     print "test3:", total_days
    
56. 
    
57. 
    
58.     for month_curr in range(1, curList[1]+1):
    
59.         if month_curr == curList[1]:
    
60.             total_days += curList[2]
    
61.         else:
    
62.             total_days += num_daysOfmonth(curList[0], month_curr)
    
63.     print "您好，今天是您入职第%d天" % total_days

复制代码

yang_zhong_well

余欲渔 发表于 2017-4-11 11:29
我是先算年,再是月,最后算日,分别加入入职天数

你这个有点问题：当天2016-2-28，入职天数是560，你这个运行之后是558.

shigure_takimi

1. def isRunnian(year):
   
2.     return (year%4==0 and year%100!=0) or year%400 == 0
   
3. 
   
4. daysOfPingnain = [31,28,31,30,31,30,31,31,30,31,30,31]
   
5. daysOfRunnian = [31,29,31,30,31,30,31,31,30,31,30,31]
   
6. 
   
7. def getDay(year1, month1, date1, year2, month2, date2):
   
8.     days1 = days2 = 0
   
9.     if year2 < year1 or (year2 == year1 and month2 < month1) or (year2 == year1 and month2 == month1 and date2 < date1):
   
10.         return '当前时间应不能早于入职时间！'
    
11.     else:
    
12.         days1 = sum(daysOfRunnian[:month1])+date1 if isRunnian(year1) else sum(daysOfPingnain[:month1])+date1
    
13.         for year in range(year1, year2):
    
14.             days2 += 366 if isRunnian(year) else 365
    
15.         days2 += sum(daysOfRunnian[:month2])+date2 if isRunnian(year2) else sum(daysOfPingnain[:month2])+date2
    
16.         return '入职第{}天！'.format(days2-days1+1)
    
17. 
    
18. print(getDay(2014,8,18,2014,8,19))
    
19. print(getDay(2014,8,11,2017,12,4))
    
20. 
    
21.             
    
22. ##    >>>
    
23. ##    入职第2天！
    
24. ##    入职第1212天！
    

复制代码

AGXA

def func(n):
    if (n % 400 == 0) or (n % 100 != 0 and n % 4 == 0):
        return True
    else:
        return False

def func1(i, k):
    count = 0
    for i in range(i+1, k+1):
        if func(i):
            count += 1
    return count

a = {'year':2014, 'month':8, 'day':18}
b = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]

year = int(raw_input('Please enter a year: '))
month = int(raw_input('Please enter a month: '))
day = int(raw_input('Please enter a day: '))

if month == a['month'] and day == a['day']:
    c = func1(a['year'], year)
    total = 366 * c + 365 * (year - a['year'] - c)
    print total
elif month >= a['month']:
    if day >= a['day']:
        c = func1(a['year'], year)
        total = 366*c+365*(year-a['year']-c)+sum(b[a['month']:month+1])+day-a['day']
        print total
    else:
        c = func1(a['year'], year)
        total = 366*c+365*(year-a['year']-c)+sum(b[a['month']+1:month])+day+b[a['month']-1] - a['day']
        print total
elif month < a['month']:
    c = func1(a['year'], year-1)
    total = 366 * c + 365 * (year - a['year'] - c - 1) + sum(b[a['month']+1:]) +sum(b[:month]) + b[a['month']-1] - a['day'] + day
    print total

AGXA

冬雪雪冬 发表于 2017-4-10 00:00
先判断闰年，再计算是一年的第几天。

厉害厉害

瞬秒爆加速

1. def fun(yy,mm,dd,YY,MM,DD):
   
2.     a = [31,28,31,30,31,30,31,31,30,31,30,31]
   
3.     l = [366 if y%4==0 or y%400==0 and y%100!=0 else 365 for y in range(2015,2017)]
   
4.     a[1] = 29 if YY%4==0 or YY%400==0 and YY%100!=0 else 28
   
5.     b = sum(l)+sum(a[:MM-1])+DD
   
6.     a[1] = 29 if YY%4==0 or YY%400==0 and YY%100!=0 else 28
   
7.     b = b+sum(a[mm-1:])-18
   
8.     return b
   
9. 
   
10. if __name__=="__main__":
    
11.     print(fun(2014,8,18,2017,4,19))

复制代码

moc

我的结果是1006天，对吗？

Agoni

冬雪雪冬 发表于 2017-4-10 00:00
先判断闰年，再计算是一年的第几天。

膜拜一下

Agoni

moc 发表于 2018-3-10 14:53
我的结果是1006天，对吗？

结果是975

victor.xu

1. def leap(n):
   
2.     if (n % 4 == 0 and n % 100 != 0) or (n % 400 == 0):
   
3.         return 1
   
4.     else:
   
5.         return 0
   
6. print('时间格式：YYYY-MM-DD')
   
7. print('入职时间：2014-08-18')
   
8. Y = 2014
   
9. M = 8
   
10. D = 18
    
11. Date = input('请输入当前日期：\n')
    
12. Sum = 0
    
13. day = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
    
14. lis_Date = Date.split('-')
    
15. Year = int(lis_Date[0])
    
16. Month = int(lis_Date[1])
    
17. Day = int(lis_Date[2])
    
18. Flag_Leap = []
    
19. for i in range(2014, Year + 1):
    
20.     Flag_Leap.append(leap(i))
    
21. for j in range(2015, Year):
    
22.     Sum = Sum + 365 + Flag_Leap[j - 2014]
    
23. if Month >2:
    
24.     Sum_T = sum(day[:Month - 1]) + Flag_Leap[-1] + Day
    
25. else:
    
26.     Sum_T = sum(day[: Month - 1]) + Day
    
27. Sum_E = sum(day[M:]) + day[M - 1] - D + 1
    
28. Sum = Sum + Sum_T + Sum_E
    
29. print('当前日期为：%s' % Date)
    
30. print('入职第%d天-小陆' % Sum)

复制代码

我的结果是976天

victor.xu

Agoni 发表于 2018-3-10 22:00
结果是975

我算的是976天呢？包含了入职当天和当前2017-04-19这一天。

新手潘包邮

看不懂

jrro452

先把自己的笨办法贴上，然后来学习大佬的优秀方案~~另外有谁能教我一下怎么用代码模式发代码啊····
year = 2014
month = 8
day =18
def caculatedays(years,months,days):
    days1=[31,28,31,30,31,30,31,31,30,31,30,31]
    days2=[31,29,31,30,31,30,31,31,30,31,30,31]
    pastdays = 0
    for i in range(1000,years):
        if (i%4==0 and i%100!=0) or (i%100==0 and i%400==0):
            pastdays+=sum(days2)
        else:
            pastdays+=sum(days1)
    if (years%4==0 and years%100!=0) or (years%100==0 and years%400==0):
        for x in range(months-1):
            pastdays+=days2[x]
        pastdays+=days
    else:
        for x in range(months-1):
            pastdays+=days1[x]
        pastdays+=days
    return pastdays
dateTime = input('请输入当前的年月日，空格隔开').split()
for i in range(len(dateTime)):
    dateTime[i]=int(dateTime[i])
joindate = caculatedays(year,month,day)
workdate = caculatedays(dateTime[0],dateTime[1],dateTime[2])
print('入职第%d天-小陆'%(workdate-joindate))

小庆子

1. '''不想判断平年闰年 (￢︿&#811;&#831;￢☆)'''
   
2. now = input('老哥，今天是几几年几月几日哈？（输入格式：1970-10-25）：').split('-')
   
3. month = [(1,31),(2,28),(3,31),(4,30),(5,31),(6,30),(7,31),(8,31),(9,30),(10,31),(11,30),(12,31)]
   
4. day1 = (int(now[0]) - 2014)*365
   
5. day2 = 0
   
6. for i in range(1,int(now[1])):
   
7.     day2 += int(month[i][1])
   
8. day2 = day2 - 212
   
9. day3 = int(now[2]) - 18
   
10. day = day1 + day2 + day3
    
11. print('斯国一，你已经入职了%s天了呢！'%day)
    

复制代码

萧丹夜

1. Year,Month,Day = map(int,input('请输入年月日(以-间隔)：').split('-'))
   
2. Run = [0,31,29,31,30,31,30,31,31,30,31,30,31]
   
3. Pin = [0,31,28,31,30,31,30,31,31,30,31,30,31]
   
4. PrYear,PrMonth,PrDay = 2014 , 8 , 18
   
5. count = 1
   
6. CurYear = Year
   
7. while True :
   
8.     if Year != PrYear and CurYear == Year:
   
9.         if Year % 400 == 0 or ( Year % 100 != 0 and Year % 4 == 0 ):
   
10.             for i in range(0,Month):
    
11.                 count += Run[i]
    
12.             count += Day
    
13.         else :
    
14.             for i in range(0,Month):
    
15.                 count += Pin[i]
    
16.             count += Day
    
17.         CurYear = Year - 1
    
18.         Month = 13
    
19.     if CurYear != PrYear :
    
20.         if CurYear % 400 == 0 or ( CurYear % 100 != 0 and CurYear % 4 == 0 ):
    
21.             for i in range(0,13):
    
22.                 count += Run[i]
    
23.         else :
    
24.             for i in range(0,13):
    
25.                 count += Pin[i]
    
26.         CurYear -= 1
    
27.     if CurYear == PrYear and Year != PrYear :
    
28.         for i in range(PrMonth + 1,Month):
    
29.             count += Pin[i]
    
30.         count += ( 31 - 18 )
    
31.         break
    
32.    
    
33.     if CurYear == PrYear or Year == PrYear :
    
34.         if Month == PrMonth :
    
35.             count += ( Day - PrDay )
    
36.         else:
    
37.             for i in range(PrMonth + 1,Month):
    
38.                 count += Pin[i]
    
39.             count += ( 31 - 18 + Day )
    
40.         break
    
41.    
    
42. print('入职第%d天-小陆'%count)

复制代码

quan-renda

str_in=input("请输入入职日期，格式为yyyymmdd：")
str_out=input("请输入当天日期，格式为yyyymmdd：")
y=int(str_in[0:4])
m=int(str_in[4:6])
d=int(str_in[6:8])
y1=int(str_out[0:4])
m1=int(str_out[4:6])
d1=int(str_out[6:8])
lst=[0,31,28,31,30,31,30,31,31,30,31,30,31]
year=y
result=[]
for year in (range(y,y1+1)):
    if (year%4==0 and year%100!=0) or year%400==0:
        if year==y and m<=2:
            result.append(sum(lst[m:])+1-d)
        if year==y1 and m1>2:
            result.append(sum(lst[0:m1]+1+d1))
        else:
            result.append(366)
    else:
        if year==y:
            result.append(sum(lst[m:])-d)
        elif year==y1:
            result.append(sum(lst[0:m1])+d1)
        else:
            result.append(365)
print("今天是入职的第%d天" %(sum(result)))

冷焰溶冰

import time
import datetime
strtime = time.strftime("%Y-%m-%d").split("-")
print(strtime)

access_protect = [2014,8,18]
sum_day = 0
month_day = [31,28,31,30,31,30,31,31,30,31,30,31]
if int(strtime[0]) - access_protect[0] > 0:
    count_year = (int(strtime[0])-access_protect[0]-1)*365 + sum([14,30,31,30,31])
    count_day = sum(month_day[:int(strtime[1])-1]) + int(strtime[2])
else:
    count_year = 0
    count_day = sum(month_day[access_protect[1]:int(strtime[1])]) + int(strtime[2]) -17

sum_day = count_year + count_day
print(sum_day)


date1 = datetime.datetime(2014,8,18)
date2 = datetime.datetime(2018,9,25)

daty_c = (date2-date1).days
print(daty_c)

北城以北灬

1. def leap_year(year):
   
2.     if year % 400 == 0 or (year % 4 == 0 and year % 100 != 0):
   
3.         return True
   
4.     else:
   
5.         return False
   
6. 
   
7. 
   
8. def lead_time(date):
   
9.     ref = [0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
   
10.     days = sum(ref[:date[1]]) + date[2]
    
11.     if leap_year(date[0]) and date[1] > 2:
    
12.         days += 1
    
13.     return days
    
14. 
    
15. 
    
16. # date_1:入职日期   date_2：当前日期
    
17. date_1 = [int(x) for x in input("请输入入职时间(例1999/1/1)：").split('/')]
    
18. date_2 = [int(x) for x in input("请输入当前日期(例1999/1/1)：").split('/')]
    
19. 
    
20. # days_1:入职那年的第几天  days_2:当前日期到入职那年1月1日的时间差
    
21. days_1 = lead_time(date_1)
    
22. days_2 = 0
    
23. 
    
24. for year in range(date_1[0], date_2[0]):
    
25.     if leap_year(year):
    
26.         days_2 += 366
    
27.     else:
    
28.         days_2 += 365
    
29. 
    
30. result = days_2 + lead_time(date_2) - days_1 + 1
    
31. print(result)

复制代码

1. 请输入入职时间(例1999/1/1)：2014/8/18
   
2. 请输入当前日期(例1999/1/1)：2017/4/19
   
3. 976

复制代码

panheng

1. 
   
2. import re
   
3. def get_days(month,day):                                     #计算当年天数
   
4.     monthlist = [1,2,3,4,5,6,7,8,9,10,11,12]
   
5.     daylist = [31,28,31,30,31,30,31,31,30,31,30,31]
   
6.     days = 0
   
7.     for each in monthlist:
   
8.         if monthlist.index(each)+1 < month:
   
9.             days += daylist[monthlist.index(each)]
   
10.     days += day
    
11.     return days
    
12. def leap_day(year):                                          #计算闰年天数
    
13.     leap_days = 0
    
14.     for _ in range(2014,year):
    
15.         if (_ % 4 == 0 and _ % 100 != 0) or _ % 400 == 0:
    
16.             leap_days += 1
    
17.     return leap_days
    
18. if __name__ == '__main__':
    
19.     date = input("请输入日期：年月日")
    
20.     datelist = re.findall(r'\d+', date)
    
21.     year = int(datelist[0])
    
22.     month = int(datelist[1])
    
23.     day = int(datelist[2])
    
24.     result = (year - 2014)*365        #计算结算日期前整年天数
    
25.     result = result + get_days(month,day) - get_days(8,18) + leap_day(year) + 1 #加上本年天数，减去8月18日天数，在加上入职第一
    
26.     if (year % 4 == 0 and year % 100 != 0) or year % 400 == 0:   #加上本年闰年天数
    
27.         if month > 2:
    
28.             result += 1
    
29.     print("%s是小陆入职的第 %s 天"%(date,result))

复制代码

修改了下，考虑到截至年份为闰年是否计算闰年天数