用循环怎么写这个代码啊？

春风得意

total = 0
shopping_price_1 = 13.9
shopping_price_2 = 12.1
shopping_price_3 = 14.3
shopping_price_4 = 15.2
total = total + shopping_price_1
total = total + shopping_price_2
total = total + shopping_price_3
total = total + shopping_price_4

和vvv

用一个列表装上所有变量：

ls = [13.9,12.1,14.3,15.2]
total = 0
for i in ls:
    total += i

print(total)

gopythoner

楼上正解

china25qd

楼上上正解

marmot

2楼正解
还可以

result = sum([13.9,12.1,14.3,15.2])

瓦蓝

五行缺五行

我是用列表
total=0
shopping_price=[13.9,12.1,14.3,15.2]
for i in shopping_price:
    total=total+i

春风得意

首先谢谢各位热心的帮助解答。但是，我理解的应该是怎么在循环里依次取出变量shopping_price_1,2,3,4的值后再加上total。也就是变量名称随着循环变化。

sunnychou

total = 0
shopping_price = [13.9,12.1,14.3,15.2]
for i in shopping_price:
    total += i
    print(total)

china25qd

春风得意 发表于 2017-6-20 08:15
首先谢谢各位热心的帮助解答。但是，我理解的应该是怎么在循环里依次取出变量shopping_price_1,2,3,4的值后 ...

变量名是定值，不可随着循环变化，否则地址会出现错误（事实上也没有语言有这样的功能，也没必要）
唯一的方法是，你在循环的时候可这样打印：

j = 0
for i in Is:
    total += i
    j += 1
    print("total = total + shopping_price_" + str(j) + "\n (shopping_price_" + str(j) + " = " + str(i) +")")

这样至少在程序运行结果显示上可以满足你的需求

春风得意

total = 0
shopping_price_1 = 13.9
shopping_price_2 = 14.1
shopping_price_3 = 12.3
shopping_price_4 = 15.2
for i in '1234':
   total += eval('shopping_price_' + i)
print('total=%.2f' % total)