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python零基础入门20课时中的动手做做,问题是
找出藏在长字符串中的密码,密码的埋藏点符合下规律:
a)每位密码为单个小写字母
b)每位密码的左右两边均有且只有三个大写字母
我按照课后参考答案打的如下代码:
str1 = '''ACFlCTLIQlAIVMTqHFkswqbDDHtpgcWaXSSglUYKE
lqNsYCyaQXBzrFUbkAUAWAKrDgDtAlGMBqWQhpEwquZqWZJpslUfMllCwWptqINjrOBTLuPzwvXNbLCx
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qKWGc'''
countA = 0 #统计前边的大写字母
countB = 0 #统计小写字母
countC = 0 #统计后边的大写字母
length = len(str1)
for i in range(length):
if str1[i] == '\n':
continue
"""|如果str1[i]是大写字母:
|-- 如果已经出现小写字母:
|-- -- 统计后边的大写字母
|-- 如果未出现小写字母:
|-- -- 清空后边的大写字母的统计
|-- -- 统计前边的大写字母
"""
if str1[i].isupper():
if countB == 1:
countC += 1
else:
countA +=1
countC = 0
"""|如果str1[i]是小写字母:
|-- 如果小写字母前边不是三个大写字母(不符合条件):
|-- -- 清空所有记录,重新统计
|-- 如果小写字母前边是三个大写字母(符合条件):
|-- -- 如果已经存在小写字母:
|-- -- -- 清空所有记录,重新统计(出现两个小写字母)
|-- -- 如果该小写字母是唯一的:
|-- -- -- countB记录出现小写字母,准备开始统计countC
"""
if str1[i].islower():
if countA !=3:
countA = 0
countB = 0
countC = 0
else:
if countB:
countA = 0
countB = 0
countC = 0
else:
countB = 1
countC = 0
target = i
"""|如果前边和后边都是三个大写字母:
|-- 如果后边第四个字母也是大写字母(不符合条件):
|-- -- 情况记录B和C,重新统计
|-- 如果后边仅有三个大写字母(符合条件):
|-- -- 打印结果,并清空所有记录,进入下一轮统计
"""
if countA == 3 and countC == 3:
if (i+1)!= length and str[i+1].isupper():
countB = 0
countC = 0
else:
print(str1[target],end='')
countA = 3
countB = 0
countC = 0
运行结果是这个,不知道什么原因
|
-
|