Python：每日一题 94（答题领鱼币）

冬雪雪冬 · 发表于 2017-9-7 19:12:40

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要给班上同学的成绩排名次，规则如下：
成绩从高往低排，如果有成绩相同的名次相同，但后续的名次要算前面的总人数。
比如，两个100分的都是第一名，紧接着的99分的是第三名，而不是第二名。

给出一个列表，是全班的成绩：

score = [('A', 80), ('B', 86), ('C', 92), ('D', 87), ('E', 88), ('F', 85),
('G', 86), ('H', 89), ('I', 88), ('J', 94), ('K', 94), ('L', 80),
('M', 83), ('N', 80), ('O', 88), ('P', 94), ('Q', 82), ('R', 84),
('S', 96), ('T', 100), ('U', 82), ('V', 81), ('W', 94), ('X', 81),
('Y', 89), ('Z', 92)]

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要求最后打印出如下的结果：三列分别是名次，姓名和成绩

1 T 100
2 S 96
3 J 94
3 K 94
3 P 94
3 W 94
7 C 92
7 Z 92
9 H 89
9 Y 89
11 E 88
11 I 88
11 O 88
14 D 87
15 B 86
15 G 86
17 F 85
18 R 84
19 M 83
20 Q 82
20 U 82
22 V 81
22 X 81
24 A 80
24 L 80
24 N 80

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我的解法：

游客，如果您要查看本帖隐藏内容请回复

Noregret · 发表于 2017-9-7 20:27:00

本帖最后由 Noregret 于 2017-9-7 21:07 编辑

score = [('A', 80), ('B', 86), ('C', 92), ('D', 87), ('E', 88), ('F', 85),
      ('G', 86), ('H', 89), ('I', 88), ('J', 94), ('K', 94), ('L', 80),
      ('M', 83), ('N', 80), ('O', 88), ('P', 94), ('Q', 82), ('R', 84),
      ('S', 96), ('T', 100), ('U', 82), ('V', 81), ('W', 94), ('X', 81),
      ('Y', 89), ('Z', 92)]

a = sorted(score, key=lambda x:x[1])
a.reverse()

b = []
for each in a:
tuple1 = [each[0], each[1]]
b.append(tuple1)

print(b)
for each in range(1, 27):
b[each - 1].insert(0, each)

for c in range(1, 27):
if b[c - 1][2] == b[c - 2][2]:
      b[c - 1][0] = b[c - 2][0]

print(b[c - 1][0], b[c - 1][1], b[c - 1][2])

bush牛 · 发表于 2017-9-7 20:53:17

def score():
score = [('A', 80), ('B', 86), ('C', 92), ('D', 87), ('E', 88), ('F', 85),
('G', 86), ('H', 89), ('I', 88), ('J', 94), ('K', 94), ('L', 80),
('M', 83), ('N', 80), ('O', 88), ('P', 94), ('Q', 82), ('R', 84),
('S', 96), ('T', 100), ('U', 82), ('V', 81), ('W', 94), ('X', 81),
('Y', 89), ('Z', 92)]
score.sort(key=lambda k: k[1], reverse=True)
flag = 1
score[0] = score[0] + (flag,)
for i in range(1,len(score)):
if score[i][1] == score[i-1][1]:
score[i] = score[i] + (score[i-1][2],)
flag += 1
else:
flag += 1
score[i] = score[i] + (flag,)
return score
if __name__ == '__main__':
score = score()
for i in range(len(score)):
print(score[i][2],score[i][0],score[i][1])

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chunchun2017 · 发表于 2017-9-7 21:07:48

score = [('A', 80), ('B', 86), ('C', 92), ('D', 87), ('E', 88), ('F', 85),
('G', 86), ('H', 89), ('I', 88), ('J', 94), ('K', 94), ('L', 80),
('M', 83), ('N', 80), ('O', 88), ('P', 94), ('Q', 82), ('R', 84),
('S', 96), ('T', 100), ('U', 82), ('V', 81), ('W', 94), ('X', 81),
('Y', 89), ('Z', 92)]
score.sort(key=lambda d:d[1],reverse=True)
index0 = 1
print('1',score[0][0],score[0][1])
for i in range(1,len(score)):
if(score[i][1]==score[i-1][1]):
print(index0,score[i][0],score[i][1])
else:
index0 = i+1
print(i+1,score[i][0],score[i][1])

复制代码

运行结果：
1 T 100
2 S 96
3 J 94
3 K 94
3 P 94
3 W 94
7 C 92
7 Z 92
9 H 89
9 Y 89
11 E 88
11 I 88
11 O 88
14 D 87
15 B 86
15 G 86
17 F 85
18 R 84
19 M 83
20 Q 82
20 U 82
22 V 81
22 X 81
24 A 80
24 L 80
24 N 80

请按任意键继续. . .

左手十字 · 发表于 2017-9-7 21:13:36

本帖最后由左手十字于 2017-9-7 22:47 编辑

score = [('A', 80), ('B', 86), ('C', 92), ('D', 87), ('E', 88), ('F', 85),
('G', 86), ('H', 89), ('I', 88), ('J', 94), ('K', 94), ('L', 80),
('M', 83), ('N', 80), ('O', 88), ('P', 94), ('Q', 82), ('R', 84),
('S', 96), ('T', 100), ('U', 82), ('V', 81), ('W', 94), ('X', 81),
('Y', 89), ('Z', 92)]
def score_sorted(list_sc):
new_list = sorted(zip(dict(list_sc).values(),dict(list_sc).keys()),reverse= True)
number = 1
flog =1
list1=[new_list[0][0]]
for score,name in new_list:
if score in list1:
print(number,name,score)
flog+=1
else:
number = flog
print(number,name,score)
list1.append(score)
flog+=1
score_sorted(score)

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ChrisYang · 发表于 2017-9-7 21:19:26

本帖最后由 ChrisYang 于 2017-9-7 21:43 编辑

e = [('A', 80), ('B', 86), ('C', 92), ('D', 87), ('E', 88), ('F', 85),
('G', 86), ('H', 89), ('I', 88), ('J', 94), ('K', 94), ('L', 80),
('M', 83), ('N', 80), ('O', 88), ('P', 94), ('Q', 82), ('R', 84),
('S', 96), ('T', 100), ('U', 82), ('V', 81), ('W', 94), ('X', 81),
('Y', 89), ('Z', 92)]
scores=[]#该列表只有成绩
for i in e:
score=i[1]
scores.append(score)
names=[]#该列表只有名字
for i in e:
name=i[0]
names.append(name)
score=list(zip(scores,names))
score.sort(reverse=True)#（成绩，名字）正序
lis=[]#（名次，名字，成绩）里面是元组形式
for i in range(1,len(e)+1):
lis.append([i,score[i-1][1],score[i-1][0]])
for i in range(1,len(e)):
if lis[i][2]==lis[i-1][2]:
lis[i][0]=lis[i-1][0]
for each in lis:
print(each[0],each[1],each[2])
————————————————————————————
运行结果
===================== RESTART: D:\Python36-32\caogao.py =====================
1 T 100
2 S 96
3 W 94
3 P 94
3 K 94
3 J 94
7 Z 92
7 C 92
9 Y 89
9 H 89
11 O 88
11 I 88
11 E 88
14 D 87
15 G 86
15 B 86
17 F 85
18 R 84
19 M 83
20 U 82
20 Q 82
22 X 81
22 V 81
24 N 80
24 L 80
24 A 80
>>>

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ChrisYang · 发表于 2017-9-7 21:44:17

ChrisYang 发表于 2017-9-7 21:19

改过来了，刚刚发错了版本

左手十字 · 发表于 2017-9-7 22:21:42

改过来了

醉挽丶南风 · 发表于 2017-9-8 00:16:44

本帖最后由醉挽丶南风于 2017-9-8 00:17 编辑

score = [('A', 80), ('B', 86), ('C', 92), ('D', 87), ('E', 88), ('F', 85),
('G', 86), ('H', 89), ('I', 88), ('J', 94), ('K', 94), ('L', 80),
('M', 83), ('N', 80), ('O', 88), ('P', 94), ('Q', 82), ('R', 84),
('S', 96), ('T', 100), ('U', 82), ('V', 81), ('W', 94), ('X', 81),
('Y', 89), ('Z', 92)]
score.sort(key=lambda item:item[1],reverse=True)
for i in range(len(score)):
if i>0:
if score[i][1]!=score[i-1][1]:
now=i+1
else:
now=i+1
print(now,score[i][0],score[i][1])

复制代码

jerryxjr1220 · 发表于 2017-9-8 06:38:24

score.sort(key=lambda n: n[1], reverse=True)
for m,n in enumerate(score):
c = m+1 if n[1]!=score[m-1][1] else c
print(c,n[0],n[1])

复制代码

baicel21314 · 发表于 2017-9-8 08:28:51

how happy to this

白牙 · 发表于 2017-9-8 11:11:58

这个真不会偷窥下

schweinfan · 发表于 2017-9-8 16:23:00

本帖最后由 schweinfan 于 2017-9-8 16:25 编辑

score = [('A', 80), ('B', 86), ('C', 92), ('D', 87), ('E', 88), ('F', 85),
('G', 86), ('H', 89), ('I', 88), ('J', 94), ('K', 94), ('L', 80),
('M', 83), ('N', 80), ('O', 88), ('P', 94), ('Q', 82), ('R', 84),
('S', 96), ('T', 100), ('U', 82), ('V', 81), ('W', 94), ('X', 81),
('Y', 89), ('Z', 92)]
rank = sorted(score, key = lambda e: e[1], reverse = True)
rank[0] = (1,) + rank[0]
temp = rank[0][2]
print(rank[0][0], rank[0][1], rank[0][2])
for i in range(1,len(rank)):
if rank[i][1] != temp:
rank[i] = (i + 1,) + rank[i]
temp = rank[i][2]
else:
rank[i] = (rank[i-1][0],) + rank[i]
temp = rank[i][2]
print(rank[i][0], rank[i][1], rank[i][2])

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输出：

1 T 100
2 S 96
3 J 94
3 K 94
3 P 94
3 W 94
7 C 92
7 Z 92
9 H 89
9 Y 89
11 E 88
11 I 88
11 O 88
14 D 87
15 B 86
15 G 86
17 F 85
18 R 84
19 M 83
20 Q 82
20 U 82
22 V 81
22 X 81
24 A 80
24 L 80
24 N 80

复制代码

solomonxian · 发表于 2017-9-8 18:24:51

先生成索引，再用字典把相同的分数的排名变成同一个

def fun(a):
lst = list(enumerate(sorted(a, key=lambda x: x[1],reverse=True), 1))
dic = {j[1]:i for i,j in lst[::-1]}
for _,k in lst:
print(dic[k[1]],*k)

复制代码

疯子的快乐 · 发表于 2017-9-8 19:50:01

有鱼币吗

wc365 · 发表于 2017-9-8 22:48:17

score = [('A', 80), ('B', 86), ('C', 92), ('D', 87), ('E', 88), ('F', 85),
('G', 86), ('H', 89), ('I', 88), ('J', 94), ('K', 94), ('L', 80),
('M', 83), ('N', 80), ('O', 88), ('P', 94), ('Q', 82), ('R', 84),
('S', 96), ('T', 100), ('U', 82), ('V', 81), ('W', 94), ('X', 81),
('Y', 89), ('Z', 92)]
#冒泡法排序
for i in range(len(score)):
for j in range(i+1,len(score)):
if score[i][1] < score[j][1]:
score[i], score[j] = score[j], score[i]
#处理序号
for i in range(len(score)):
if score[i][1] != score[i-1][1]:
print(i+1,score[i][0],score[i][1])
n = i+1
else:
print(n,score[i][0],score[i][1])

复制代码

zyq940 · 发表于 2017-9-11 16:24:07

本帖最后由 zyq940 于 2017-9-11 16:36 编辑

score = [('A', 80), ('B', 86), ('C', 92), ('D', 87), ('E', 88), ('F', 85),
('G', 86), ('H', 89), ('I', 88), ('J', 94), ('K', 94), ('L', 80),
('M', 83), ('N', 80), ('O', 88), ('P', 94), ('Q', 82), ('R', 84),
('S', 96), ('T', 100), ('U', 82), ('V', 81), ('W', 94), ('X', 81),
('Y', 89), ('Z', 92)]
score = sorted(score, key=lambda x:x[1])
score.reverse()
rank1 = 1
rank2 = 1
for i in range(0,25):
if score[i][1] != score[i+1][1] and score[i][1] != score[i-1][1]:
print(rank1,score[i][0],score[i][1])
rank1 += 1
rank2 += 1
elif score[i][1] == score[i+1][1]:
print(rank1,score[i][0],score[i][1])
rank2 += 1
elif score[i][1] != score[i+1][1] and score[i][1] == score[i-1][1]:
print(rank1,score[i][0],score[i][1])
rank2 += 1
rank1 = rank2
print(rank1,score[i+1][0],score[i+1][1])

复制代码

Linco · 发表于 2017-9-11 23:24:47

score = [('A', 80), ('B', 86), ('C', 92), ('D', 87), ('E', 88), ('F', 85),
('G', 86), ('H', 89), ('I', 88), ('J', 94), ('K', 94), ('L', 80),
('M', 83), ('N', 80), ('O', 88), ('P', 94), ('Q', 82), ('R', 84),
('S', 96), ('T', 100), ('U', 82), ('V', 81), ('W', 94), ('X', 81),
('Y', 89), ('Z', 92)]
sort = sorted(score, key=lambda student: student[1], reverse=True)
out = []
temp = {}
for index, student in enumerate(sort):
rank = temp.get(student[1], index + 1)
out.append((rank, *student))
temp[student[1]] = rank
print('\n'.join('%s %s %s' % (n[0], n[1], n[2]) for n in out))

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faye_vip · 发表于 2017-9-12 15:33:03

score = [('A', 80), ('B', 86), ('C', 92), ('D', 87), ('E', 88), ('F', 85),
      ('G', 86), ('H', 89), ('I', 88), ('J', 94), ('K', 94), ('L', 80),
      ('M', 83), ('N', 80), ('O', 88), ('P', 94), ('Q', 82), ('R', 84),
      ('S', 96), ('T', 100), ('U', 82), ('V', 81), ('W', 94), ('X', 81),
      ('Y', 89), ('Z', 92)]
score.sort(key = lambda a : a[1],reverse = True)
index = 1
print(str(index),score[0][0],score[0][1])
for i in range(len(score)):
if score[i][1] == score[i+1][1]:
      print(index+1,score[i+1][0],score[i+1][1])
else:
      index = i + 1
      print(index+1,score[i+1][0],score[i+1][1])
print(score)

pillar · 发表于 2017-9-13 10:32:38

score = [('A', 80), ('B', 86), ('C', 92), ('D', 87), ('E', 88), ('F', 85),

      ('G', 86), ('H', 89), ('I', 88), ('J', 94), ('K', 94), ('L', 80),

      ('M', 83), ('N', 80), ('O', 88), ('P', 94), ('Q', 82), ('R', 84),

      ('S', 96), ('T', 100), ('U', 82), ('V', 81), ('W', 94), ('X', 81),

      ('Y', 89), ('Z', 92)]
score.sort(key=lambda s:s[1],reverse=True)
i=0
n=0
for each in score:
if score[i][1]>score[i+1][1]:
      print(i+1,score[i][0],score[i][1])
      i=i+1
else:
      n=i
      print(n,score[i][0],score[i][1])
      i=i+1

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