[已解决]请教一个字符串替换问题

sige

C:\Users\HE\Desktop\1.png
如图，我想将下一行的开始时间替换掉上一行的末尾时间，也就是用00:00:01,005替换掉00:00:02,882，00:00:02,909替换掉00:00:04,026，以此类推……求帮助，谢谢！

1
00:00:00,003 --> 00:00:02,882
You cannot improve your past

2
00:00:01,005 --> 00:00:04,026
but you can improve your future

3
00:00:02,909 --> 00:00:06,810
Once time is wasted

4
00:00:04,071 --> 00:00:07,089
life is wasted

5
00:00:06,081 --> 00:00:08,154
you can

最佳答案

月排行榜 / 总排行榜

冬雪雪冬

2017-9-7 19:54:53

1. str1 = '''1
   
2. 00:00:00,003 --> 00:00:02,882
   
3. You cannot improve your past
   
4. 
   
5. 2
   
6. 00:00:01,005 --> 00:00:04,026
   
7. but you can improve your future
   
8. 
   
9. 3
   
10. 00:00:02,909 --> 00:00:06,810
    
11. Once time is wasted
    
12. 
    
13. 4
    
14. 00:00:04,071 --> 00:00:07,089
    
15. life is wasted
    
16. 
    
17. 5
    
18. 00:00:06,081 --> 00:00:08,154
    
19. you can'''
    
20. list1 = str1.split('\n')
    
21. str2 = ''
    
22. time = list1[-2][:12]
    
23. for i in range(-6, -len(list1), -4):
    
24.     list1[i] = list1[i][:17] + time
    
25.     time = list1[i][:12]
    
26. print('\n'.join(list1))

复制代码

1. 1
   
2. 00:00:00,003 --> 00:00:01,005
   
3. You cannot improve your past
   
4. 
   
5. 2
   
6. 00:00:01,005 --> 00:00:02,909
   
7. but you can improve your future
   
8. 
   
9. 3
   
10. 00:00:02,909 --> 00:00:04,071
    
11. Once time is wasted
    
12. 
    
13. 4
    
14. 00:00:04,071 --> 00:00:06,081
    
15. life is wasted
    
16. 
    
17. 5
    
18. 00:00:06,081 --> 00:00:08,154
    
19. you can

复制代码

跳转到最佳答案楼层

sige

图片似乎发不出来，我把需要处理的文字方法code里面，方便大家复制，谢谢啦

1. 1
   
2. 00:00:00,003 --> 00:00:02,882
   
3. You cannot improve your past
   
4. 
   
5. 2
   
6. 00:00:01,005 --> 00:00:04,026
   
7. but you can improve your future
   
8. 
   
9. 3
   
10. 00:00:02,909 --> 00:00:06,810
    
11. Once time is wasted
    
12. 
    
13. 4
    
14. 00:00:04,071 --> 00:00:07,089
    
15. life is wasted
    
16. 
    
17. 5
    
18. 00:00:06,081 --> 00:00:08,154
    
19. you can

复制代码

冬雪雪冬

1. str1 = '''1
   
2. 00:00:00,003 --> 00:00:02,882
   
3. You cannot improve your past
   
4. 
   
5. 2
   
6. 00:00:01,005 --> 00:00:04,026
   
7. but you can improve your future
   
8. 
   
9. 3
   
10. 00:00:02,909 --> 00:00:06,810
    
11. Once time is wasted
    
12. 
    
13. 4
    
14. 00:00:04,071 --> 00:00:07,089
    
15. life is wasted
    
16. 
    
17. 5
    
18. 00:00:06,081 --> 00:00:08,154
    
19. you can'''
    
20. list1 = str1.split('\n')
    
21. str2 = ''
    
22. time = list1[-2][:12]
    
23. for i in range(-6, -len(list1), -4):
    
24.     list1[i] = list1[i][:17] + time
    
25.     time = list1[i][:12]
    
26. print('\n'.join(list1))

复制代码

1. 1
   
2. 00:00:00,003 --> 00:00:01,005
   
3. You cannot improve your past
   
4. 
   
5. 2
   
6. 00:00:01,005 --> 00:00:02,909
   
7. but you can improve your future
   
8. 
   
9. 3
   
10. 00:00:02,909 --> 00:00:04,071
    
11. Once time is wasted
    
12. 
    
13. 4
    
14. 00:00:04,071 --> 00:00:06,081
    
15. life is wasted
    
16. 
    
17. 5
    
18. 00:00:06,081 --> 00:00:08,154
    
19. you can

复制代码

ba21

1. str1='''1
   
2. 00:00:00,003 --> 00:00:02,882
   
3. You cannot improve your past
   
4. 
   
5. 2
   
6. 00:00:01,005 --> 00:00:04,026
   
7. but you can improve your future
   
8. 
   
9. 3
   
10. 00:00:02,909 --> 00:00:06,810
    
11. Once time is wasted
    
12. 
    
13. 4
    
14. 00:00:04,071 --> 00:00:07,089
    
15. life is wasted
    
16. 
    
17. 5
    
18. 00:00:06,081 --> 00:00:08,154
    
19. you can
    
20. '''
    
21. 
    
22. strlist = str1.splitlines() #按行分割字符串
    
23. strlist2 =[]
    
24. strtemp = ''
    
25. for each in strlist:
    
26.      if each.find('-->') > -1:
    
27.           if strtemp == '':
    
28.                strtemp = each
    
29.           else:
    
30.                uetime = strtemp.split('-->')[1].strip() #获取上一条结束时间并去掉前后空格
    
31.                strtemp = each
    
32.                etime = each.split('-->')[1].strip()#获取当前结束时间并去掉前后空格
    
33.                each =  uetime + ' --> ' + etime
    
34. 
    
35.      strlist2.append(each)
    
36. 
    
37. str2 = '\n'.join(strlist2) #重组字符串
    
38. print(str2)
    
39.          
    

复制代码

sige

冬雪雪冬 发表于 2017-9-7 19:54

非常感谢冬雪版主

sige

ba21 发表于 2017-9-7 20:11

赞赞赞，多谢