Python：每日一题 121

冬雪雪冬 · 发表于 2017-11-5 17:03:37

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本帖最后由冬雪雪冬于 2017-11-10 15:19 编辑

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题目：
这是一个排序的练习。
有如下的一个列表：
list1 = [684, 6299800, 6041028, 2458660284, 937, 7857867, 384147026736, 888843160862, 270]
要求先求出各位之和，如果结果不是一位数，继续此步骤，直到成为1~9的数字，例如684各位之和为18，再次运算为9，然后对其排序，排序不是从1到9，也不是从9到1，是按照下面列表的次序。
list2 = [1, 6, 7, 4, 9, 3, 2, 5, 8]
最后给出list1排序后的列表。

SixPy · 发表于 2017-11-5 18:05:00

本帖最后由 SixPy 于 2017-11-5 18:18 编辑

list1 = [684, 6299800, 6041028, 2458660284, 937, 7857867, 384147026736, 888843160862, 270]
list2 = [1, 6, 7, 4, 9, 3, 2, 5, 8]
order = {n:i for i,n in enumerate(list2)}
def x(n):
while n>9:
n = sum(int(i)for i in str(n))
return order[n]
list1.sort(key=x)
print(list1)
#[937, 384147026736, 6299800, 684, 2458660284, 270, 6041028, 7857867, 888843160862]

复制代码

wc365 · 发表于 2017-11-6 00:11:16

#数字n先求出各位之和，如果结果不是一位数，继续此步骤，直到成为1~9的数字
def sumbit(n):
while n > 9:
total = 0
for each in list(str(n)):
total += eval(each)
n = total
return n
#序列list1按照序列list2的顺序排列
def sortlist(list1,list2):
list3 = [[sumbit(x),x] for x in list1]
list4 = []
for i in list2:
for j in range(len(list3)):
if i == list3[j][0]:
list4.append(list3[j][1])
return list4
list1 = [684, 6299800, 6041028, 2458660284, 937, 7857867, 384147026736, 888843160862, 270]
list2 = [1, 6, 7, 4, 9, 3, 2, 5, 8]
print(sortlist(list1,list2))

复制代码

BngThea · 发表于 2017-11-6 09:49:21

list1 = [684, 6299800, 6041028, 2458660284, 937, 7857867, 384147026736, 888843160862, 270]
list2 = [1, 6, 7, 4, 9, 3, 2, 5, 8]
tar = []
for each in list1:
while each > 9:
each = sum(map(int, str(each)))
tar.append(each)
tar = sorted(tar, key = lambda x: list2.index(x))
print(tar)

复制代码

wyp02033 · 发表于 2017-11-6 11:03:03

本帖最后由 wyp02033 于 2017-11-6 11:16 编辑

def get_index(num):
if num < 10:
return num
else:
new_num = 0
for each in str(num):
new_num += int(each)
return get_index(new_num)
list1 = [684, 6299800, 6041028, 2458660284, 937, 7857867, 384147026736, 888843160862, 270]
index_list = []
for each in list1:
index_list.append(get_index(each))
the_order = {1:0, 6:1, 7:2, 4:3, 9:4, 3:5, 2:6, 5:7, 8:8}
num_order = []
for each in index_list:
num_order.append(the_order[each])
sorted_order = sorted(num_order)
new_list = []
for each in sorted_order:
new_list.append(list1[num_order.index(each)])
list1.remove(list1[num_order.index(each)])
num_order.remove(each)
print(new_list)

复制代码

排序结果：[937, 384147026736, 6299800, 684, 2458660284, 270, 6041028, 7857867, 888843160862]

bush牛 · 发表于 2017-11-6 14:15:02

def len_sum(n:int):
if n < 10:
return n
else:
n = str(n)
s_sum = sum(int(i) for i in n)
if len(str(s_sum)) > 1:
s_sum = len_sum(s_sum)
return s_sum
list1 = [684, 6299800, 6041028, 2458660284, 937, 7857867, 384147026736, 888843160862, 270]
list2 = [1, 6, 7, 4, 9, 3, 2, 5, 8]
list3 = [(len_sum(i), i) for i in list1]
from collections import defaultdict
d = defaultdict(list)
for k, v in list3:
d[k].append(v)
list4 = [d[i] for i in list2 if i in d.keys()]
from itertools import chain
print(list(chain(*list4)))

复制代码

无边落木 · 发表于 2017-11-6 14:57:10

看看答案

ytbihpl2017 · 发表于 2017-11-6 16:03:43

真的想不出来

飞非妃飞飞 · 发表于 2017-11-6 16:27:17

比较菜，代码很陋，就做个简单的
---------------------------
def toList(numbers):
List = [str(num) for num in numbers]
return List

if __name__ == "__main__":
L = toList([12345, 349, 8989009]);
a=[]
t=[[int(i) for i in I]for I in L]
print(t)
print(type(len(t)))
for i in t:
   print(sum(i))
   if sum(i)>10:
   a.append(sum(i))
print(a)
K=toList(a)
if __name__ == "__main__":
   print(K)
   ba = []
   bt = [[int(i) for i in I] for I in K]
   print(bt)
   for i in bt:
      print(sum(i))
      ba.append(sum(i))
   print(ba)

renze · 发表于 2017-11-6 17:18:39

list1 = [684, 6299800, 6041028, 2458660284, 937, 7857867, 384147026736, 888843160862, 270]
list2 = []
def doit(i):
add = 0
sum1 = list(str(i))
for j in sum1:
add = add + int(j)
return add
def sort(in_list):
for j in range(len(in_list)) :
if in_list[j] == 1:
in_list[j] = 1
elif in_list[j] == 6:
in_list[j] = 2
elif in_list[j] == 7:
in_list[j] = 3
elif in_list[j] == 4:
in_list[j] = 4
elif in_list[j] == 9:
in_list[j] = 5
elif in_list[j] == 3:
in_list[j] = 6
elif in_list[j] == 2:
in_list[j] = 7
elif in_list[j] == 5:
in_list[j] = 8
elif in_list[j] == 8:
in_list[j] = 9
return in_list
for i in list1:
add = doit(i)
while add > 9 :
add = doit(add)
list2.append(add)
list2 = sort(list2)
#list2.sort()
print(list2)

复制代码

p5494846 · 发表于 2017-11-6 17:55:41

本帖最后由 p5494846 于 2017-11-6 17:58 编辑

list1 = [684, 6299800, 6041028, 2458660284, 937, 7857867, 384147026736, 888843160862, 270]
def fun_sum(x): #定义求位和的函数
while x > 9:
x = str(x)
y = 0
for n in x:
y += int(n)
x = y
return x
list = map(fun_sum,list1) #得到初始的列表
list_tmp = []
dict = {'1':'1','6':'2','7':'3','4':'4','9':'5','3':'6','2':'7','5':'8','8':'9'}
for num in list:
tmp = dict[str(num)]
list_tmp.append(tmp)
list_tmp.sort() #根据映射关系得到值的列表
#以下步骤是利用索引根据dict的值查找键
list_fin = []
key_list = []
value_list = []
for key,value in dict.items():
key_list.append(key)
value_list.append(value)
for x in list_tmp:
index = value_list.index(x)
y = key_list[index]
list_fin.append(y) #根据映射关系反过来得到最终列表
print(list_fin)

复制代码

solomonxian · 发表于 2017-11-6 18:25:42

递归，各位数相加直到只剩一位数，按要求排序

list1 = [684, 6299800, 6041028, 2458660284, 937, 7857867, 384147026736, 888843160862, 270]
list2 = [1, 6, 7, 4, 9, 3, 2, 5, 8]
new_sum = lambda n: n if n<10 else new_sum(sum(int(i) for i in str(n)))
new_list1 = [new_sum(num) for num in list1]
print(sorted(new_list1, key=lambda x: list2.index(x)))

复制代码

ooxx7788 · 发表于 2017-11-6 20:37:23

def foo(num):
while num >=10:
num = sum(map(int,list(str(num))))
return num
list1 = [684, 6299800, 6041028, 2458660284, 937, 7857867, 384147026736, 888843160862, 270]
dict1 = {v:k for k,v in zip(list(map(int,(list('123456789')))),[1, 6, 7, 4, 9, 3, 2, 5, 8])}
d = {v:k for k,v in dict1.items()}
x = [d[s] for s in sorted([dict1[r] for r in map(foo,list1)])]
y = list(map(foo,list1))
temp = list(zip(y,list1))
result = []
for i in x:
for each in range(len(temp)):
if i == temp[each][0]:
result.append(temp.pop(each)[1])
break
result
[937, 384147026736, 6299800, 684, 2458660284, 270, 6041028, 7857867, 888843160862]

复制代码

感觉写的有点麻烦

编程新血 · 发表于 2017-11-6 21:34:16

list1 = [684, 6299800, 6041028, 2458660284, 937, 7857867, 384147026736, 888843160862, 270]
list2 = [1, 6, 7, 4, 9, 3, 2, 5, 8]
print(list1)
print(list2)
'''各位加到9'''
def addnum9(x):
while x>9:
      u=0
      for i in str(x):
         u+=int(i)
      x=u
return x
'''list1的数字的排序'''
listcc=[]
for i in list1:
listcc.append(addnum9(i))
'''组合在一起'''
list4=list(zip(listcc,list1))

list5=[]
for i in list2:
for i2 in list4:
      if i2[0]==i:
         list5.append(i2[1])
print(list5)

lihw · 发表于 2017-11-6 23:38:21

list1 = [684, 6299800, 6041028, 2458660284, 937, 7857867, 384147026736, 888843160862, 270]
list2=[]
list3=[]
list4=[1, 6, 7, 4, 9, 3, 2, 5, 8]
he=0
def fun(list1):
for i in list1:
he=sum(map(int,str(i)))
if he <=9:
list2.append(he)
else:
list1=[]
list1.append(he)
fun(list1)
return (sorted(list2,key=list4.index))

复制代码

xindong · 发表于 2017-11-7 08:35:28

数位相加用递归倒是没有什么问题。

按照规定的序列排序倒是有点烧脑子，代码看着有点繁琐。不过结果在这里：
排序前：
[9, 7, 3, 9, 1, 3, 6, 8, 9]
排序后：
[1, 6, 7, 9, 9, 9, 3, 3, 8]

# -*- coding: utf-8 -*-
"""
Created on Mon Nov 6 15:59:02 2017
"""
import numpy as np
def numSum(Num):
NumOfDigitals = int(np.log10(Num))
numAdd=0;
for i in range(NumOfDigitals, 0, -1):
if ( i == NumOfDigitals):
Digital = int(Num / pow(10, i))
numAdd=Digital
remain = Num - Digital*pow(10,i)
else:
Digital = int(remain / pow(10, i))
numAdd += Digital
remain = remain - Digital*pow(10,i)
return numAdd + remain
def digitalSum(Num):
dig_sum = Num
while(dig_sum > 9):
dig_sum = numSum(dig_sum)
return dig_sum
list1 = [684, 6299800, 6041028, 2458660284, 937, 7857867, 384147026736, 888843160862, 270]
list2 = [1, 6, 7, 4, 9, 3, 2, 5, 8]
nlist1=[]
for i in list1:
nlist1.append(digitalSum(i))
print(nlist1)
nlist1=[]
for i in list1:
dig_sum = digitalSum(i)
if(len(nlist1)==0):
nlist1.append(dig_sum)
else:
index_j = 0
flag=0
order_old = list2.index(nlist1[index_j])
order_new = list2.index(dig_sum)
while (order_new > order_old and flag==0): #and index_j<len(nlist1)-1):
index_j = index_j + 1
if (index_j < len(nlist1)):
order_old = list2.index(nlist1[index_j])
else:
flag=1
if (flag==1):
nlist1.append(dig_sum)
else:
nlist1.insert(index_j,dig_sum)
print(nlist1)

复制代码

colinshi · 发表于 2017-11-7 10:56:30

本帖最后由 colinshi 于 2017-11-7 10:58 编辑

from functools import reduce
list1 = [684, 6299800, 6041028, 2458660284, 937, 7857867, 384147026736, 888843160862, 270]
def add2(x, y):
return int(x) + int(y)
def CaiFen(element):
a = element
while a > 9:
a = int(reduce(add2,list(str(a))))
return a
g=[]
for i in list1:
g.append(CaiFen(i))
z=zip(g,list1)
dic={}
for k,v in z:
dic[v]=k
l=[]
list2 = [1, 6, 7, 4, 9, 3, 2, 5, 8]
for i in list2:
for v,k in dic.items():
if i == k:
l.append(v)
print(l)

复制代码

代码感觉写的有点长，没有精简。

cyz1993 · 发表于 2017-11-7 11:39:10

list1= [684,6299800,6041028,2458660284, 937,7857867,384147026736,888843160862,270]
list2 = [1, 6, 7, 4, 9, 3, 2, 5, 8]
num=0
d={}
list3=[]
jud=False
while not jud:
jud=True
for each in list1:
jud=jud and (each < 10)
for each in list1:
if each >= 10:
for i in str(each):
num +=int(i)
else:
num=each
list3.append(num)
num=0
list1=list3[:]
list3=[]
for i in range(9):
d[list2[i]]=i
list1.sort(key=lambda x:d[x])

复制代码

天使骑魔鬼 · 发表于 2017-11-7 19:06:41

list1 = [684, 6299800, 6041028, 2458660284, 937, 7857867, 384147026736, 888843160862, 270]
list2 = [1, 6, 7, 4, 9, 3, 2, 5, 8]
list3 = []
while not(set(list1) < set(list2) or set(list1) == set(list2)):
for i in range(9):
      list1[i] = sum(map(int,list(str(list1[i]))))
for each in list2:
for i in range(len(list1)):
      if list1[i] == each:
         list3.append(list1[i])
print(list3)

WD2017 · 发表于 2017-11-8 00:32:20

需要什么基础才能写出，老师？

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