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发表于 2021-4-27 00:35:37
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测试题
0. 10 个
1. 不打印 B
2. a、b、c 都是
3. a = 14,b = 5,c = 9
4.
- #include <stdio.h>
- int main(void)
- {
- int x, z;
- printf("请输入一个整数:");
- scanf("%d", &x);
- if (x >= 0) {
- z = x;
- } else {
- z = -x;
- }
- printf("%d 的绝对值是:%d\n", x, z);
- return 0;
- }
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5
A.- #include <stdio.h>
- int main(void)
- {
- int size, flag = 1;
- float cost = 1.0, bill = 0.0;
- printf("请输入size:");
- scanf("%d", &size);
- // 带 goto 版本
- if (size > 12) {
- goto a;
- }
- goto b;
- a: cost = cost * 1.05;
- flag = 2;
- b: bill = cost * flag;
- printf("带 goto 版本:cost = %f, flag = %d, bill = %f\n", cost, flag, bill);
-
- cost = 1, flag = 1, bill = 0;
- // 不带 goto 版本
- if (size > 12) {
- cost = cost * 1.05;
- flag = 2;
- }
- bill = cost * flag;
- printf("不带 goto 版本:cost = %f, flag = %d, bill = %f\n", cost, flag, bill);
- return 0;
- }
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B.- #include <stdio.h>
- int main(void)
- {
- int ibex, sheds, help;
- printf("请输入ibex:");
- scanf("%d", &ibex);
- // 带 goto 版本
- if (ibex > 14) {
- goto a;
- }
- sheds = 2;
- goto b;
- a: sheds = 3;
- b: help = 2 * sheds;
- printf("help = %d\n", help);
- // 不带 goto 版本
- if (ibex > 14) {
- sheds = 3;
- } else {
- sheds = 2;
- }
- help = 2 * sheds;
- printf("help = %d\n", help);
- return 0;
- }
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C
- #include <stdio.h>
- int main(void)
- {
- int score, count = 0;
- // 带goto版本
- readin: scanf("%d", &score);
- if (score < 0) {
- goto stage2;
- }
- count ++;
- goto readin;
- stage2: printf("count = %d\n", count);
- // 不带goto版本
- count = 0;
- while (scanf("%d", &score), !(score < 0)) {
- count++;
- }
- printf("count = %d\n", count);
- return 0;
- }
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动动手
0.
- #include <stdio.h>
- int main(void)
- {
- float x_money = 10000.0, h_money = 10000.0;
- int years = 0;
- while (x_money >= h_money)
- {
- years++;
- x_money += 10000.0 * 0.1;
- h_money *= 1.05;
- }
- printf("%d年后,黑夜的投资额超过小甲鱼!\n", years);
- printf("小甲鱼的投资额是:%.2f\n", x_money);
- printf("黑夜的投资额是:%.2f\n", h_money);
- return 0;
- }
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1.
- #include <stdio.h>
- int main(void)
- {
- float money = 4000000.0;
- int years = 0;
- while (money > 0) {
- years++;
- money -= 500000.0;
- money *= 1.08;
- }
- printf("%d年后,笑甲鱼败光了所有的家产,再次回到一贫如洗……\n", years);
- return 0;
- }
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2.
- #include <stdio.h>
- int main(void)
- {
- double item, quarter_pi;
- int num, sign;
- for (num = 1, sign = 1; (item = 1.0 / num) >= 1e-8; num += 2, sign = -sign) {
- quarter_pi += sign * item;
- }
- printf("Pi小数点后前7位为:%.7f\n", quarter_pi * 4);
- return 0;
- }
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3.
- #include <stdio.h>
- int main(void)
- {
- int f_1 = 1, f_2 = 1, cur, month;
- for (month = 22; month > 0; month -= 1) {
- cur = f_1 + f_2;
- f_1 = f_2;
- f_2 = cur;
- }
- printf("两年后的兔子总计%d对\n", cur);
- return 0;
- }
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