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测试题:
0.10个。
1.0个。
2.a,b,c。
3.a=14,c=9,b=5。
4.#include <stdio.h>
int main()
{
int x,z;
printf("请输入一个整数:\n");
scanf("%d",&x);
z = x > 0 ? x : -x;
printf("求绝对值得:z = %d",z);
return 0;
}
5.
A.
if(size > 12)
{
cost = cost * 1.05;
flag = 2;
}
bill = cost * flag;
B.
if (ibex > 14)
{
sheds = 3;
}
else
{
sheds = 2;
}
help = 2*sheds;
C.
while(1)
{
scanf("%d",&score);
if(score<0)
{
break;
}
count++;
}
printf("count=%d\n",count);
动动手:
0.
#include <stdio.h>
#include <math.h>
int main()
{
int count = 0;
double i = 10000,j = 10000;
double a = 10000,b = 10000;
while (b <= a)
{
a = i + (1000*count);
b = j * pow(1.05,count);
count++;
}
printf("%d年后,黑夜的投资额超过小甲鱼!\n",count);
printf("小甲鱼的投资额是:%d\n",a);
printf("黑夜的投资额是:%d\n",b);
return 0;
}
1.
#include <stdio.h>
int main()
{
int year = 0;
double money = 4000000;
double this_year_start_money = 4000000;
printf("初始资金:%.2f元\n",money);
while (money >= 0)
{
year++;
money = money - 500000;
money = money * 1.08;
printf("第%d年末,取出50万元后剩余%.2f元\n",year,money);
}
printf("%d年之后,小甲鱼败光了所有的家产,再次回到一贫如洗......\n",year);
return 0;
}
2.
#include <stdio.h>
#include <math.h>
int main()
{
double i = -3,pi,sum = 0;
while (fabs(i)<100000000)
{
sum = sum + (1/i);
if (i < 0)
{
i = fabs(i) + 2;
}
else
{
i = fabs(i) + 2;
i = -i;
}
}
pi = 4 * (1 + sum);
printf("pi = %.8f\n",pi);
return 0;
}
3.不会 |
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