0. 10个
1. 0个
2. a
3. a=14,b = 5,c = 9
4. z = x>=0 ? x : -x
5.
Aif (size > 12)
{
cost = cost * 1.05;
flag = 2;
}
bill = cost * flag;
B:if (ibex > 14)
{
sheds = 3;
}
else
{
sheds = 2;
}
help = 2 * sheds;
C,do {
scanf("%d", &score);
count++;
} while (score > 0);
printf("count = %d\n", count);
0.#include <stdio.h>
#include <math.h>
int main()
{
double money = 10000;
double xjy, hy;
int time = 0;
xjy = 10000, hy = 10000;
while (1)
{
if (xjy < hy)
{
break;
}
xjy = 10000, hy = 10000;
xjy = xjy + money * 0.10 * time;
hy = hy * pow(1 + 0.05, time);
time++;
}
printf("%d年后,黑夜的投资额超过小甲鱼 !\n", time);
printf("小甲鱼的投资额是:%.2lf\n", xjy);
printf("黑夜的投资额是:%.2lf\n", hy);
return 0;
}
1.#include <stdio.h>
int main()
{
double money = 4000000;
int time = 0;
while (money > 0)
{
money -= 500000;
money += money * 0.08;
time++;
}
printf("%d年之后,小甲鱼败光了所有的家产,再次回到一贫如洗......", time);
return 0;
}
2.#include <stdio.h>
#include <math.h>
int main()
{
int i, sign = 1;
double pi = 0, s = 1;
for (i = 1; fabs(s) > 1 / 1e8; i += 2)
{
s = sign * (1.0 / i);
sign *= -1;
pi += s;
}
pi = 4 * pi;
printf("pi = %.7lf", pi);
return 0;
}
3.#include <stdio.h>
int main()
{
int a = 0, b = 1;
int i;
for (i = 0; i < 24; i++)
{
int t = b;
b = a + b;
a = t;
}
printf("两年后有%d对兔子", b);
return 0;
}
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