S1E16：拾遗 | 课后测试题及答案

KXHH · 发表于 2021-10-18 20:24:31

‘’‘

犯点小错误 · 发表于 2021-10-18 21:16:59

仟渝 · 发表于 2021-10-18 22:48:17

tang818875 · 发表于 2021-10-19 03:07:54

0. 10

1. 10

2. c, b, a

3.

4. z = x >= 0 ? x: -x

5.
A.

if(size > 12) {
    cost = cost * 1.05;
    flag = 2;
} else {
    bill = cost * flag;
}

B.

if(ibex > 14) {
   sheds = 3;
} else {
    sheds = 2;
    help = 2 * sheds;
}

C. if(score < 0) {
printf("count = %d\n", count);
} else {
count ++;
scanf("%d", &score);
}

1501672283 · 发表于 2021-10-19 10:00:06

fast1314 · 发表于 2021-10-19 10:54:30

0.10
1.0
2.a = b;
b = c;
c= 5;
3.

978063782 · 发表于 2021-10-19 17:16:41

0: 10
1: 10
2:

a=5
b=5
c=5

3:

a=4
b=3
c=8

4:

5:

A:
if (size > 12)
{
      cost = cost * 1.05;
      break;
}
      flag = 2;
      bill = cost * flag;

B:

if (ibex > 14)
{
      sheds = 3;
      break;
}

   sheds = 3;
   help = 2 * sheds;

C:

      scanf("%d", &score);
if (score < 0)
{
      printf("count = %d\n", count);
}

动动手:
0:
#include <stdio.h>
#include <stdlib.h>
#include <math.h>

int main()
{
double x=10000, y=10000,c=0;

for (int i = 1; i < 1000; i++)
{
      c = 10000 * 0.1;
      x = x + c;
      y = y + y * 0.05;

      if (y > x)
      {
         printf("%d年后y超越x\n",i);
         printf("x=%f\ny=%f",x,y);
         break;
      }

}

return 0;
}

1:

double x=4000000, y=500000,c=0;

for (int i = 1; i < 1000; i++)
{
      x = x - y;
      x = x * 0.08 + x;

      if (x<=0)
      {
         printf("%d年后破产",i);
         break;
      }

}

2:

double PI=(2/3), x=3,y=0;

for (int n = 1; n < 10000; n++)
{
      if (n > 1)
      {
         x = x + 2;
         if (n % 2 != 0)
         {
            PI = PI - (1 / x);
         }
         if (n % 2 == 0)
         {
            PI = PI + (1 / x);
         }
      }
      printf("%.7f\n",PI);
}

ONMAkane · 发表于 2021-10-19 17:40:30

#include<stdio.h>

int main()
{
float x, z;

printf("请输入数字：");
scanf("%f", &x);

if(x<0)
{
   z = -x;
}
else
{
   z = x;
}

printf("他的绝对值为%.2f", z);
return 0;
}if(size>12)
{
  cost *= 1.05;
  flag = 2;
}
bill = cost * flag;if(ibex>14)
{
  sheds = 3;
}
else
{
  sheds = 2;
}
help = 2 * sheds;while(a = scanf("%d", &score))
{
   if(score<0)
   {
      printf("count = %d", count);
      break;
   }
   else
   {
      count++;
   }
}#include<stdio.h>
#include<math.h>

int main()
{
int year = 1;
float xjy, hy;

for(year = 1;year>=1;year++)
{
   xjy = 10000 * (1 + 0.1 * year);
   hy = 10000 * pow(1 + 0.05,year);
   if(hy>xjy)
   {
      printf("%d年后，黑夜的投资额大于小甲鱼！\n", year);
      printf("小甲鱼的投资额是：%.2f\n", xjy);
      printf("黑夜的投资额是：%.2f", hy);
      break;
   }

}
return 0;
}#include<stdio.h>
#include<math.h>

int main()
{
int year;
double a;

for(year = 1; year>=1; year++)
{
      a = 4000000 * pow(1.08,year)-500000 * (pow(1.08,year) * (1 - pow(1/1.08,year - 1)))/(1 - (1/1.08));
      if(a<=0)
      {
         printf("%d年之后，小甲鱼败光了所有的家产，再次回到一贫如洗...", year);
         break;
      }
}
return 0;
}#include<stdio.h>
#include<math.h>

int main()
{
double a = 0;
int n;
for(n = 0;n>=0;n++)
{
   a = (pow(-1,n))*1/(1 + 2*n) + a;
   if(1/(1 + 2*n)<pow(10,-8))
   {
      printf("%.7f", 4*a);
      break;
   }

}

return 0;
}#include<stdio.h>

int main()
{
int a = 2, b = 1;
for(b = 1;b<=24;b++)
{
      if(b<=4)
      {
      a = b * 2;
      }
      else
      {
      a = a + (b - 3)*2;
      }

}
printf("两年后一共%d只兔子", a);
return 0;
}

屋子很大 · 发表于 2021-10-19 18:52:17

10
10
a

lrw · 发表于 2021-10-19 20:49:02

林江楠 · 发表于 2021-10-19 21:25:50

飞花落尽 · 发表于 2021-10-19 23:27:11

0.100
1.10
2.c,b,a
3.16 6 11
4. z = x >= 0 ? x : -x;
5.if (size > 12)
{
      cost = cost * 1.05;
      flag = 2;
}
bill = cost * flag;

sheds = 2;
if (ibex > 14)
{
      sheds = 3;
}
help = 2 * sheds;

while (readin)
{
if (score < 0)
{
         printf("count = %d\n", count);
         break;
}
count++;
readin = scanf("%d", &score);

dabo · 发表于 2021-10-20 11:49:05

_(:з」∠)_

2213216806 · 发表于 2021-10-20 14:50:04

炫U炫 · 发表于 2021-10-20 15:12:17

mmoli · 发表于 2021-10-20 18:57:14

Ang_Ti · 发表于 2021-10-20 19:23:07

31

AdiosSpike · 发表于 2021-10-20 20:15:45

今天也是努力的一天

白白叭叭叭叭 · 发表于 2021-10-21 12:27:18

0.
10个
1.
0个
2.
a, b, c
3.
a = 14; b = 5; c = 9;
4.
z = x >= 0 ? x : -x;

5.

A.
if (size > 12)
{
      cost = cost * 1.05;
      flag = 2;
}
bill = cost * flag;

B.

if (ibex > 14)
{
      sheds = 3;
}
else
{
      sheds = 2;
}
help = 2 * sheds;

C.

while (1)
{
scanf("%d", &score);
if (score < 0)
{
      break;
}
count++;
}
printf("count = %d\n", count);

昵称加载错误 · 发表于 2021-10-21 12:35:38

0.
10个
1.
0个
2.
a, b, c
3.
a = 14; b = 5; c = 9;
4.
z = x >= 0 ? x : -x;

5.

A.
if (size > 12)
{
      cost = cost * 1.05;
      flag = 2;
}
bill = cost * flag;

B.

if (ibex > 14)
{
      sheds = 3;
}
else
{
      sheds = 2;
}
help = 2 * sheds;

C.

while (1)
{
scanf("%d", &score);
if (score < 0)
{
      break;
}
count++;
}
printf("count = %d\n", count);

动动手
0.

#include <stdio.h>
#define PRINCIPAL 10000

int main()
{
        float principal1 = PRINCIPAL, principal2 = PRINCIPAL;
        int year;
        
        for (year = 0; principal1 >= principal2; year++)
        {
                principal1 += PRINCIPAL * 0.1;
                principal2 *= 1 + 0.05; 
        }
        
        printf("%d年后 , 黑夜的投资额超过小甲鱼!\n小甲鱼的投资额是 : %.2f\n黑夜的投资额是 : %.2f\n", year, principal1, principal2);
        
        return 0;
}

1.

#include <stdio.h>

int main ()
{
        int year;
        float money = 400;
        
        for (year = 0; money > 0; year++)
        {
                money -= 50;
                money *= 1.08;
        }
        
        printf("%d年之后 , 小甲鱼败光了所有的家产 , 再次回到一贫如洗......\n", year);
        
        return 0;
}

2.

#include <stdio.h>
#include <math.h>

int main()
{
        double sum = 0, num = 1.0;
        
        do 
        {
                sum += num;
        }while (fabs(num = -1.0/(num < 0 ? 1.0/num - 2 : 1.0/num + 2)) >= pow(10, -8));

        printf("%.7f", 4 * sum);
        
        return 0;
}

3.

#include <stdio.h>

int main()
{
        int a = 1, b = 1, temp;
        
        for (int i = 2; i < 24; i++)
        {
                temp = b;
                b = a + b;
                a = temp;
        }
        
        printf("两年后可以繁殖%d次\n", b);
        
        return 0;
}

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[课后作业] S1E16：拾遗 | 课后测试题及答案