|
发表于 2021-10-19 17:40:30
|
显示全部楼层
#include<stdio.h>
int main()
{
float x, z;
printf("请输入数字:");
scanf("%f", &x);
if(x<0)
{
z = -x;
}
else
{
z = x;
}
printf("他的绝对值为%.2f", z);
return 0;
}if(size>12)
{
cost *= 1.05;
flag = 2;
}
bill = cost * flag;if(ibex>14)
{
sheds = 3;
}
else
{
sheds = 2;
}
help = 2 * sheds;while(a = scanf("%d", &score))
{
if(score<0)
{
printf("count = %d", count);
break;
}
else
{
count++;
}
}#include<stdio.h>
#include<math.h>
int main()
{
int year = 1;
float xjy, hy;
for(year = 1;year>=1;year++)
{
xjy = 10000 * (1 + 0.1 * year);
hy = 10000 * pow(1 + 0.05,year);
if(hy>xjy)
{
printf("%d年后,黑夜的投资额大于小甲鱼!\n", year);
printf("小甲鱼的投资额是:%.2f\n", xjy);
printf("黑夜的投资额是:%.2f", hy);
break;
}
}
return 0;
}#include<stdio.h>
#include<math.h>
int main()
{
int year;
double a;
for(year = 1; year>=1; year++)
{
a = 4000000 * pow(1.08,year)-500000 * (pow(1.08,year) * (1 - pow(1/1.08,year - 1)))/(1 - (1/1.08));
if(a<=0)
{
printf("%d年之后,小甲鱼败光了所有的家产,再次回到一贫如洗...", year);
break;
}
}
return 0;
}#include<stdio.h>
#include<math.h>
int main()
{
double a = 0;
int n;
for(n = 0;n>=0;n++)
{
a = (pow(-1,n))*1/(1 + 2*n) + a;
if(1/(1 + 2*n)<pow(10,-8))
{
printf("%.7f", 4*a);
break;
}
}
return 0;
}#include<stdio.h>
int main()
{
int a = 2, b = 1;
for(b = 1;b<=24;b++)
{
if(b<=4)
{
a = b * 2;
}
else
{
a = a + (b - 3)*2;
}
}
printf("两年后一共%d只兔子", a);
return 0;
} |
|