0.
100
1.
10
2.
a,b,c,
3.
6, 6 ,10
4.
c=x>-x?x:-c;
5.
if (size > 12)
{
cost = cost * 1.05;
flag = 2;
}
else
{
bill = cost * flag;
}
if (ibex>14)
{
sheds=3;
}
else
{
sheds=2;
help = 2*sheds;
}
do
{
scanf(%d,&score);
if(score<0)
{
printf("count=%d\n",count);
}
count++;
}
while(score>=0);
0.#include<stdio.h>
#include<math.h>
int main()
{
float a,b;
_Bool flag=0;
int n=0;
for(n=0;;n++)
{
a=10000+10000*n*0.1;
b=10000*pow(1.05,n);
if(b>a)
{
printf(" %d 年后,黑夜的投资额超过小甲鱼!\n",n);
printf("小甲鱼的投资额是:%.2f\n",a);
printf("黑夜的投资额是:%.2f\n",b);
break;
}
}
return 0;
}
1。#include<stdio.h>
int main()
{
float sum=4000000;
int n=0;
for(;sum>0;n=n+1)
{
sum = sum*1.08 - 500000;
}
printf("%d年后,小甲鱼败光了所有的家产,再次回到一贫如洗......",n);
return 0;
}
2.#include<stdio.h>
#include<math.h>
int main()
{
int n=0;
float sum=0,i=1;
do
{
sum=pow(-1,n)*1/i + sum;
n++;
i+=2;
}
while(n<1000);
printf("%.7f",sum);
return 0;
}
3.#include<stdio.h>
int main()
{
int n=0;
int a[24];
for(;n<24;n++)
{ if(n>1)
{a[n]=a[n-1]+a[n-2];}
else
{a[n]=1;}
printf("%d个月后一共有%d对兔子。\n",n+1,a[n]);
}
return 0;
}
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