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发表于 2021-11-14 17:19:49
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显示全部楼层
0.
100
1.
10
2.
a,b,c,
3.
6, 6 ,10
4.
c=x>-x?x:-c;
5.
if (size > 12)
{
cost = cost * 1.05;
flag = 2;
}
else
{
bill = cost * flag;
}
if (ibex>14)
{
sheds=3;
}
else
{
sheds=2;
help = 2*sheds;
}
do
{
scanf(%d,&score);
if(score<0)
{
printf("count=%d\n",count);
}
count++;
}
while(score>=0);
0.
- #include<stdio.h>
- #include<math.h>
- int main()
- {
- float a,b;
- _Bool flag=0;
- int n=0;
- for(n=0;;n++)
- {
- a=10000+10000*n*0.1;
- b=10000*pow(1.05,n);
- if(b>a)
- {
- printf(" %d 年后,黑夜的投资额超过小甲鱼!\n",n);
- printf("小甲鱼的投资额是:%.2f\n",a);
- printf("黑夜的投资额是:%.2f\n",b);
- break;
- }
- }
- return 0;
- }
复制代码
1。
- #include<stdio.h>
- int main()
- {
- float sum=4000000;
- int n=0;
- for(;sum>0;n=n+1)
- {
- sum = sum*1.08 - 500000;
- }
- printf("%d年后,小甲鱼败光了所有的家产,再次回到一贫如洗......",n);
- return 0;
- }
复制代码
2.
- #include<stdio.h>
- #include<math.h>
- int main()
- {
- int n=0;
- float sum=0,i=1;
- do
- {
- sum=pow(-1,n)*1/i + sum;
- n++;
- i+=2;
- }
- while(n<1000);
- printf("%.7f",sum);
- return 0;
- }
复制代码
3.
- #include<stdio.h>
- int main()
- {
- int n=0;
- int a[24];
- for(;n<24;n++)
- { if(n>1)
- {a[n]=a[n-1]+a[n-2];}
- else
- {a[n]=1;}
- printf("%d个月后一共有%d对兔子。\n",n+1,a[n]);
- }
- return 0;
- }
复制代码 |
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