S1E16：拾遗 | 课后测试题及答案

eeyycc

w120400806

看答案

唯爱路哥的无颜

测试题:
0.100个
1.9个
2.a,b,c
3.a=3,b=4,c=10
4.x = x>=0?x:-x;
5.A:
if (size > 12)
{
cost = cost * 1.05;
flag = 2;
}
bill = cost*flag;
B:
If(ibex > 14)
{
sheds = 3;
}
sheds = 2;
help = 2 * sheds;
C:
If(score < 0)
{
printf(“count = %d\n”,count);
}
count++;
scanf(“%d”,&score);

动动手
0.
#include <stdio.h>
int main()
{
float sum = 10000,profit2=0,sum2=10000,total1,total2;
int n=1
;
while(total2 <= total1)
{
total1 = sum + sum * 0.1 * n;
profit2 = sum2 * 0.05;
total2 = sum2 +profit2;
sum2 += profit2;
n++;
}
printf("%d年后,黑夜的投资额超过小甲鱼!\n",n-1);
printf("小甲鱼的投资额是:%.2f\n",total1);
printf("黑夜的投资额是:%.2f\n",total2);
return 0;
}
1.
#include <stdio.h>
int main()
{
float money = 4000000,profit,cost = 500000;
int n=1;
while(money>0)
{
profit = money * 0.08;
money = money + profit - cost;
n++;
}
printf("%d年之后,小甲鱼败光了所有的家产,再次回到一贫如洗......\n",n);
return 0;
}

2.
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
int n;
float number,sum=1;
for(n=1;fabs(pow(-1,n+1)*(1/(2*(n+1)+1))) < pow(10,-8);n++)
{
number = pow(-1,n)*(1/(2*n+1));
sum += number;
}
printf("%.7f\n",sum);
return 0;
}

3.

Kieyuku-Acc

支持

不改变的节奏

回复

sgyth

dsf

欢福勇乐

已完成

quanru124

.

觉哥无所畏惧

。。。

doudou子最棒

haobang

白小蔡

阿玛尼

1

jy00822484

测试题：
0.无限个吧，因为j永远到不了10
1.10个
2.看了扩展阅读还是不懂你这题意思
3. a=14,b=5,c=9
4.
#include <stdio.h>

int main()
{
        int x;
        int z;
        printf("请输入一个数字：\n");
        scanf("%d", &x);
       
        if(x < 0)
        {
                z =(0 - x);
        }
        else
        {
                z = x;
        }
       
        printf("z的值是：%d\n", z);

        return 0;

}
5.
A.
if (size > 12)
{
         cost = cost * 1.05;
        flag = 2;
}
else
{
        bill = cost * flag;
}
B.
if (ibex > 14)
{
        goto b;
}
else
{
        sheds = 3;
        sheds = 2;
        help = 2 * sheds;
}
C.
do
{
scanf("%d", &score);
count++;
}
while (score >= 0)

printf("count = %d\n", count);
break;

动动手：
0.
#include <stdio.h>

int main()
{
        double jiayuM = 10000, heiyeM = 10000;
        int count = 0;
        do
        {
                jiayuM += 1000;
                heiyeM = heiyeM*1.05;
                count++;
        }while(jiayuM > heiyeM);
       
        printf("需要%d年后黑夜手头的Money才会超过小甲鱼\n", count);
        printf("小甲鱼的投资额是:%.2f\n", jiayuM);
        printf("黑夜的投资额是：%.2f\n", heiyeM);

        return 0;

}
1.
#include <stdio.h>
#include <math.h>

int main()
{
        int count = 1;
        double jueduizhi = 0;
        double pai = 1;
        double fenzi = 1.0;
        double fenmu;
        do
        {
                fenmu = (1+2*(count - 1));
                jueduizhi =fabs(fenzi/fenmu);
                if(count % 2 != 0)
                {
                        pai = pai + jueduizhi;
                }
                else
                {
                        pai = pai - jueduizhi;
                }
                count++;
               
                printf("现在绝对值是：%.7f\n", jueduizhi);
                printf("现在Pi的值是：%.7f\n", pai);
        }
        while(jueduizhi > 0.00000001);
       
        printf("现在Pi的值是：%.7f\n", pai);
    return 0;
}//实在不行，换了几次方案，都没成功，拿个失败品来交吧。
2.做题目的时间远远大于看视频的时间

shuangye08

0.10次
1.10次
2.a,b,c都是
3. a=14,b=4.c=8.
4.z=x>0?x:-x;
5.A:
if (size > 12)
{
       cost*=1.05
};
flag = 2;
bill = cost * flag;
B:
if (ibex > 14)
{
       sheds=2;
}
else {sheds = 2;};
help = 2 * sheds;
C:
while(count++)
{
scanf("%d"，&score)
if(score<0){break;}
}
printf("count=%d",count)

laowu3

拾遗 | 课后测试题及答案

ZERO。

1

mike890208

done

Petty_Red

1

a1062486419

1

2740881635

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