Python：每日一题 2

一步半个脚印

x= int(input('please input your profit number (the unit is ten thousand):' ))
y=0
if x <= 10 :
        y = x * 0.1
elif 10 <x <= 20 :
        y= (x-10)*0.075+10*0.1
elif 20<x<=40:
        y=(x-20)*0.05+(x-10)*0.075+10*0.1
elif 40<x<=60:
        y=(x-40)*0.03+(x-20)*0.05+(x-10)*0.075+10*0.1
elif 60<x<=100:
        y=(x-60)*0.015+(x-40)*0.03+(x-20)*0.05+(x-10)*0.075+10*0.1
elif 100 < x :
        y=(x-100)*0.01+(x-60)*0.015+(x-40)*0.03+(x-20)*0.05+(x-10)*0.075+10*0.1

print(y)

上传代码格式。。嘻嘻。

acgods

MonthProfit = int(input("请输入当月的利润："))
prize = 0
def prize(MonthProfit):
    if MonthProfit <= 100000:
        prize = MonthProfit * 0.1 
    elif 100000 < MonthProfit <= 200000:
        prize = 100000 * 0.1 + (MonthProfit - 100000)* 0.075
    elif 200000 < MonthProfit <= 400000:
        prize = 100000 * 0.1 + 100000 * 0.075 + (MonthProfit - 200000) * 0.05
    elif 400000 < MonthProfit <= 600000:
        prize = 100000 * 0.1 + 100000 * 0.075 + 200000 * 0.05 + (MonthProfit -400000) * 0.03
    elif 600000 < MonthProfit <= 1000000:
        prize = 100000 * 0.1 + 100000 * 0.075 + 200000 * 0.05 + 200000 * 0.03 + (MonthProfit - 600000) * 0.015
    else:
        prize = 100000 * 0.1 + 100000 * 0.075 + 200000 * 0.05 + 200000 * 0.03 + 400000 * 0.015 + (MonthProfit - 1000000) * 0.01
    return prize

print("本月的奖金为：" + str(prize(MonthProfit)))

FishC_TYRANT

新手·ing 发表于 2017-3-24 22:17

比我想的简洁，楼主大佬

god圣锋

def pr(proft):
    #利润(I)低于或等于10万元时，奖金可提10%
    bonus = proft + proft*0.1

    '''利润高于10万元，低于20万元时，低于10万元的部分按10%提成，
    高于10万元的部分，可提成7.5%'''
    bonus2 = bonus + (proft - 10E+4)* 0.075

    #20万到40万之间时，高于20万元的部分，可提成5%
    bonus3 = bonus2 + (proft - 2*(10E+4))* 0.05

    #40万到60万之间时高于40万元的部分，可提成3%
    bonus4 = bonus3 + (proft - 4*(10E+4))* 0.03

    #60万到100万之间时，高于60万元的部分，可提成1.5%
    bonus5 = bonus4 + (proft - 6*(10E+4))* 0.015

    #高于100万元时，超过100万元的部分按1%提成
    bonus6 = bonus5 + (proft - 10E+5)* 0.01

    return bonus,bonus2,bonus3,bonus4,bonus5,bonus6

while True:
    proft = input('请输入当月的总利润')

    if proft == '.w':
        break
    
    proft = int(proft)
    
    bonus,bonus2,bonus3,bonus4,bonus5,bonus6 = pr(proft)
    
    if (proft > 10E+5):
        print(bonus6)

    elif proft > 6*(10E+4):
        print(bonus5)

    elif proft > 4*(10E+4):
        print(bonus4)

    elif proft > 2*(10E+4):
        print(bonus3)

    elif proft > 10E+4:
        print(bonus2)

    else:
        print(bonus)

_玛莎_

i = int(input('请输入当月的利润（单位：万元）：'))
if i <= 10:
    bonus = i * 0.1
    print('应发奖金数为%s' % bonus)
elif 10 <= i <= 20:
    bonus = 10*0.1+(i-10)*0.075
    print('应发奖金数为%s' % bonus)
elif 20 <= i <= 40:
    bonus = 10*0.1+10*0.075+(i-20)*0.05
    print('应发奖金数为%s' % bonus)
elif 40 <= i <= 60:
    bonus = 10*0.1+10*0.075+20*0.05+(i-40)*0.03
    print('应发奖金数为%s' % bonus)
elif 60 <= i <= 100:
    bonus = 10*0.1+10*0.075+20*0.05+20*0.03+(i-60)*0.015
    print('应发奖金数为%s' % bonus)
else:
    bonus = 10*0.1+10*0.075+20*0.05+20*0.03+40*0.015+(i-100)*0.01
    print('应发奖金数为%s' % bonus)

whoam1python

jj = 0
fl = [100, 60, 40, 20, 10, 0]
ll = [0.01, 0.015, 0.03, 0.05, 0.075, 0.1]
lr = int(input("请输入利润:"))
for i in range(6):
    if lr > fl[i]:
        jj += (lr - fl[i]) * ll[i]
        print(jj)
        lr = fl[i]

print(jj)

liujian973

bonus_list={100000:[0.075,10000],200000:[0.05,17500],400000:[0.03,27500],600000:[0.015,33500],1000000:[0.01,3.95]}
def money(profit,bonus_list=bonus_list):
    profit_section = [i for i in bonus_list.keys() if profit >i]
    if profit_section ==[]:
        return profit*0.1
    else:
        temp =[profit_section[0]]+ bonus_list[profit_section[0]]
       
        return (profit-temp[0])*temp[1]+temp[2]
try:
    i=int(input("请输入利润"))
    print(money(i)
except:print("请输入正确的利润")

zhangjk19841984

profit=int(input('请输入当前的公司利润：--->'))
money=0
p=profit
m=money
if p<10:
    m=p*0.1
elif 10<=p<20:
    m=(p-10)*0.075+10*0.1
elif 20<=p<40:
    m=(p-20)*0.05+10*0.175
elif 40<=p<60:
    m=20*0.05+10*0.175+(p-40)*0.03
print(m)

丽啊DDer

渡漫 发表于 2017-5-21 20:43
小弟不才

就服你！

小明禅师

profit = int(input("输入净利润："))
bouns=0.0

if(profit<=100000):
    bouns=profit*0.1
elif(100000<profit<=200000):
    bouns=100000*10/100+(profit-100000)*7.5/100
elif(200000<profit<=400000):
    bouns=100000*10/100 + 100000*7.5/100 + (profit-200000)*5/100
elif(400000<profit<=600000):
     bouns=100000*10/100 + 100000*7.5/100 + 200000*5/100 + (profit-400000)*3/100
elif(600000<profit<=1000000):
     bouns=100000*10/100 + 100000*7.5/100 + 200000*5/100 + 200000*3/100 + (profit-600000)*1.5/100
elif(profit>1000000):
     bouns=100000*10/100 + 100000*7.5/100 + 200000*5/100 + 200000*3/100 + 600000*1.5/100 + (profit-1000000)*1/100

print("奖金为：",bouns)

double-lee

profit = float(input("输入当月利润: "))
bonus = 0
while profit:
    if profit <= 100000:
        bonus += profit * 0.1
        break
    elif 100000 < profit <= 200000:
        bonus += (profit - 100000) * 0.075
        profit = 100000
    elif 200000 < profit <= 400000:
        bonus += (profit - 200000) * 0.05
        profit = 200000
    elif 400000 < profit <= 600000:
        bonus += (profit - 400000) * 0.03
        profit = 400000
    elif 600000 < profit <= 1000000:
        bonus += (profit - 600000) * 0.015
        profit = 600000
    elif profit > 1000000:
        bonus += (profit - 1000000) * 0.01
        profit = 1000000
print("当月利润 %d ,应发放奖金总数为: %d"%(profit,bonus))

看了楼主的,再看自己的,太复杂了..

sunrise085

对于多次if...else...判断就不写了。我写了三个版本，第一个版本中有三个列表，分别是利润数轴列表、奖金比例列表、分段奖金列表，程序先判断利润在哪个区间，然后去查表计算总奖金。

mylist1 = [1000000,600000,400000,200000,100000,0]
mylist2 = [0.01,0.015,0.03,0.05,0.075,0.1]
mylist3 = [39500,33500,27500,17500,10000,0]
I = input('请输入当前月利润I：')
I = int(I)
for i in range(0,len(mylist1)):
        if I > mylist1[i]:
                break
fee = (I-mylist1[i]) * mylist2[i]+mylist3[i]
print ('奖金总数：',fee)

第二个版本中有两个列表，分别是利润数轴列表、奖金比例列表，直接循环计算总奖金。

mylist1 = [1000000,600000,400000,200000,100000,0]
mylist2 = [0.01,0.015,0.03,0.05,0.075,0.1]
I = 150000#input('请输入当前月利润I：')
temp = int(I)
fee = 0
for i in range(0,len(mylist1)):
        if temp > mylist1[i]:
                fee += (temp-mylist1[i]) * mylist2[i]
                temp = mylist1[i]
print ('奖金总数：',fee)

第三个版本是将第二个版本进行改进，利用函数写了一个递归，通过递归函数计算总奖金。

def fee(I):
        mylist1 = [1000000,600000,400000,200000,100000,0]
        mylist2 = [0.01,0.015,0.03,0.05,0.075,0.1]
        for i in range(0,len(mylist1)):
                if I > mylist1[i]:
                        fees = (I - mylist1[i]) * mylist2[i] + fee(mylist1[i])
                        break
        if I == 0:
                return 0
        return fees

I = input('请输入当前月利润I：')
temp = int(I)
print ('奖金总数：',fee(I))

nnxiaod

def do1(a):
    if a <= 100000L:
        return a * 0.1
    elif 100000L < a <= 200000L:
        return (a - 100000L) * 0.075 + do1(100000L)
    elif 200000L < a <= 400000L:
        return (a - 200000L) * 0.05 + do1(200000L)
    elif 400000L < a <= 600000L:
        return (a - 400000L) * 0.03 + do1(400000L)
    elif 600000L < a <= 1000000L:
        return (a - 600000L) * 0.015 + do1(600000L)
    else:
        return (a - 1000000L) * 0.01 + do1(1000000L)


if __name__ == '__main__':
    a = input("请输入利润：")
    print(do1(long(a)))

梦星

i = int(input('请输入您的利润：'))

bouns = 0


if i > 1e6:
    bouns += (i - 1e6) * 0.010
    i = 1e6
if i > 6e5:
    bouns += (i - 6e5) * 0.015
    i = 6e5
if i > 4e5:
    bouns += (i - 4e5) * 0.030
    i = 4e5
if i > 2e5:
    bouns += (i - 2e5) * 0.050
    i = 2e5
if i > 1e5:
    bouns += (i - 1e5) * 0.075
    i = 1e5
if i <= 1e5:
    bouns += i * 0.100

print(bouns)

iloverisa5206

i=float(input('請輸入當月利潤:'))
if i<=100000:
    (i*0.1)=x
    print(x)
if i>100000:
    ((i-100000)*0.75+x)=y
    print(y)
if i>200000:
    ((i-200000)*0.05+y)=z
    print(z)
if i>400000:
    ((i-400000)*0.03+z)=a
if i>600000:
    ((i-600000)*0.15+a)=s
if i>1000000:
    ((i-1000000)*0.01+s)=d
    print(d)

為什麼一直語法錯誤

Xna_MT

temp = input ('请输入当月利润数据(单位万元)：')
x= float(temp)
y=0
if x<=10:
   y=x*0.1
   print('奖金为',y*10000,'元')
elif 10<x<=20:
    y=(x-10)*0.1+x*0.075
    print('奖金为',y*10000,'元')
elif 20<x<=40:
    y=(x-20)*0.05+(x-10)*0.1+x*0.075
    print('奖金为',y*10000,'元')
elif 40<x<=60:
    y=x*0.03+(x-20)*0.05+(x-10)*0.1+x*0.075
    print('奖金为',y*10000,'元')
elif 60<x<=100:
    y=x*0.015+(x-20)*0.05+(x-10)*0.1+x*0.075
    print('奖金为',y*10000,'元')
elif 100<x:
    y=x*0.01+(x-20)*0.05+(x-10)*0.1+x*0.075
    print('奖金为',y*10000,'元')
else:
  
    print('输入有误')#---还缺少异常捕抓
   

Sneakerjj

i=int(input('当月利润:'))
if i <= 10:
    bonuses = i * 0.1
elif 10 < i <= 20:
    bonuses = 1 + (i - 10) * 0.075
elif 20 < i <= 40:
    bonuses = 1 + 0.75 + (i - 20) * 0.05
elif 40 < i <= 60:
    bonuses = 1 + 0.75 + 0.5 + (i - 20) * 0.03
elif 60 < i <= 100:
    bonuses = 1 + 0.75 + 0.5 + 0.3 + (i - 20) * 0.015
elif i > 100:
    bonuses = 1 + 0.75 + 0.5 + 0.3 + 0.15 + (i - 20) * 0.01
else:
    bonuses = 0
   
print('当月利润:%d'%i)
print('应发放奖金总数:' ,bonuses)

lwy520

def jiangjical(lirun):
    jiangjin=0
    lirun_sheng=lirun
    while(True):
        if lirun_sheng <= 100000:
            jiangjin += lirun_sheng * 0.1
            break
        
        elif 100000 < lirun_sheng <= 200000:
            jiangjin += (lirun_sheng-100000) * 0.075
            lirun_sheng=100000

        elif 200000 < lirun_sheng <= 400000:
            jiangjin += (lirun_sheng-200000) * 0.05
            lirun_sheng=200000

        elif 400000 < lirun_sheng <= 600000:
            jiangjin += (lirun_sheng-400000) * 0.03
            lirun_sheng=400000

        elif 600000 < lirun_sheng <= 1000000:
            jiangjin += (lirun_sheng-600000) * 0.015
            lirun_sheng=600000

        else:
            jiangjin += (lirun_sheng-1000000) * 0.001
            lirun_sheng=1000000

    return jiangjin

lirun=int(input("请输入月利润："))
jiangjin=jiangjical(lirun)
print(jiangjin)

苍月枫

j = 0
i = int(input('请输入该月利润(万元)： '))
if i <= 10:
    j = i * 0.1
elif i <= 20:
    j = (i -10 ) * 0.075 + 1
elif i <= 40:
    j = ( i - 20) * 0.05 + (0.075 * 10) + (0.1 * 10)
elif i <= 60:
    j = (i - 60) *  0.03 + (0.05 * 20) + (0.075 * 10)+(0.1 * 10)
elif i <= 100:
    j = (i - 100) * 0.015 + (0.03 * 20) + (0.05 * 20) + (0.075 * 10)+(0.1 * 10)
elif i > 100:
    j = (i - 100) * 0.01 + (0.015 * 40)  + (0.03 * 20) + (0.05 * 20) + (0.075 * 10)+(0.1 * 10)
print('本月的奖金为：', j ,'万元')

苍月枫

新手·ing 发表于 2017-3-24 22:17

楼主的看着简洁，但是个人感觉针对题目来说，不像纯数学方法那样通俗易懂。但是对于开发来说，这种应该比我那种一堆if语句要好吧