Python：每日一题 2

whitney7

n = int(input('请输入当月净利润：'))
pro = [0.01,0.015,0.03,0.05,0.075,0.1]
mon = [1000000,600000,400000,200000,100000,0] #成长整型
sum1 = 0
for i in range(0,6):
    if n > mon[i]:
        sum1 += (n - mon[i]) * pro[i]
        print((n - mon[i]) * pro[i])
        n = mon[i]
print('总提成为：',sum1)

流浪的杰

a = int(input('利润'))
if a <= 100000:
    print (a*0.1)
elif a <= 200000:
    print (10000+(a-100000)*0.075)
elif a <= 400000:
    print (17500+(a-200000)*0.05)
elif a <= 600000:
    print (27500+(a-400000)*0.03)
elif a <= 1000000:
    print (33500+(a-600000)*0.015)
elif a > 1000000:
    print (39500+(a-1000000)*0.01)

十月故里

1. i=int(input('净利润/万元'))
   
2. t=0
   
3. arr=[100,60,40,20,10,0]
   
4. rat=[0.01,0.015,0.03,0.05,0.075,0.1]
   
5. rang=list(zip(arr,rat))
   
6. for j in rang:
   
7.     if i>j[0]:
   
8.         t+=(i-j[0])*j[1]
   
9.         i=j[0]
   
10. print(t,'万元')

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rofok

# 企业发放的奖金根据利润提成。利润(I)低于或等于10万元时，奖金可提10%；
# 利润高于10万元，低于20万元时，低于10万元的部分按10%提成，
# 高于10万元的部分，可提成7.5%；20万到40万之间时，高于20万元的部分，可提成5%；
# 40万到60万之间时高于40万元的部分，可提成3%；
# 60万到100万之间时，高于60万元的部分，可提成1.5%，高于100万元时，超过100万元的部分按1%提成，
# 从键盘输入当月利润I，求应发放奖金总数？

print("第一种方法")
profit = float(input("输入利润(单位万元)："))
if profit < 0:
    print('输入错误请重新输入')
    profit = float(input("输入利润(单位万元)："))

bonus = 0.0
if profit <= 10:
    bonus = profit*0.1
elif (profit > 10) and (profit <= 20):
    bonus = (profit-10)*0.075 + 10*0.1
elif (profit > 20) and (profit <= 40):
    bonus = (profit-20)*0.05 + 10*0.075 + 10*0.1
elif (profit > 40) and (profit <= 60):
    bonus = (profit - 40) * 0.03 + 10 * 0.075 + 10 * 0.1 + 20*0.05
elif (profit > 60) and (profit <= 100):
    bonus = (profit - 60) * 0.015 + 10 * 0.075 + 10 * 0.1 + 20 * 0.05 + 20*0.03
elif profit > 100:
    bonus = (profit - 100) * 0.01 + 10 * 0.075 + 10 * 0.1 + 20 * 0.05 + 20*0.03 + 40*0.015

print("当月利润为", profit, "万元", "奖金为", bonus, "万元")

print("第二种方法")
# 输入利润
def inputProfit():
    try:
        profit = float(input("输入利润(单位万元)："))
        return profit
    except:
        print("输入错误")
        return inputProfit()
#计算奖金
profit = inputProfit()
profits = [0, 10, 20, 40, 60, 100]
#profits.reverse()
donuslike = [0.1, 0.075, 0.05, 0.03, 0.015, 0.01]
#donuslike.reverse()

def calculateBonus():
    bonus2 = 0.0
    if len(profits) != len(donuslike):
        print("程序异常")
        return
    for i in range(len(profits)-1):
        if (profit > profits[i]) and (profit >= profits[i+1]):
            bonus2 = bonus2 + (profits[i+1]-profits[i])*donuslike[i]
        elif (profit > profits[i]) and (profit < profits[i+1]):
            bonus2 = bonus2 + (profit - profits[i])*donuslike[i]

    # 单独比较最大值
    if profit >= profits[len(profits)-1]:
        bonus2 = bonus2 + (profit - profits[len(profits)-1])*donuslike[len(donuslike)-1]
    return bonus2


print("当月利润为", profit, "万元", "奖金为", calculateBonus(), "万元")

雁过无痕y

1. I = int(input())
   
2. 
   
3. if I <= 100000:
   
4.     award = I * 0.1
   
5. elif I <= 200000:
   
6.     award = 10000 * 0.1 + 0.75 * (I - 100000)
   
7. elif I <= 400000:
   
8.     award = 10000 * 0.1 + 0.75 * 200000 + 0.5 * (I - 200000)
   
9. elif I <= 600000:
   
10.     award = 10000 * 0.1 + 0.75 * 200000 + 0.5 * 400000 + 0.3 * (I - 400000)
    
11. elif I <= 1000000:
    
12.     award = 10000 * 0.1 + 0.75 * 200000 + 0.5 * 400000 + 0.3 * 600000 + 0.15 * (I - 600000)
    
13. elif I > 1000000:
    
14.     award = 10000 * 0.1 + 0.75 * 200000 + 0.5 * 400000 + 0.3 * 600000 + 0.15 * 1000000 + 0.01 * (I - 1000000)
    
15. 
    
16. print(award)

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可惜我只会elif

逸野散人

def my_money(temp):
    t1 = 10*0.1
    t2 = 10*0.075
    t3 = 20*0.005
    t4 = 20*0.003
    t5 = 40*0.0015
    if temp  <= 10:
        return temp*0.1
    elif 10 < temp <= 20:
        return t1 + (temp-10)*0.075
    elif 20 < temp <= 40:
        return t1 + t2 + (temp-20)*0.005
    elif 40 < temp <= 60:
        return t1+t2+t3+(temp-40)*0.003
    elif 60 < temp <= 100:
        return t1+t2+t3+t4+(temp-60)*0.0015
    elif temp > 100:
        return t1+t2+t3+t4+t5+(temp-100)*0.001

temp = int(input('请输入当月利润(单位万元): '))
if temp <= 0:
    print('公司该倒闭了')
else:
    money = my_money(temp)
    print('奖金数是(万元): ')
    print(money)
        

xucl

"""
企业发放的奖金根据利润提成。利润(I)低于或等于10万元时，奖金可提10%；
利润高于10万元，低于20万元时，低于10万元的部分按10%提成，高于10万元的部分，可提成7.5%；
20万到40万之间时，高于20万元的部分，可提成5%；
40万到60万之间时高于40万元的部分，可提成3%；
60万到100万之间时，高于60万元的部分，可提成1.5%，
高于100万元时，超过100万元的部分按1%提成，
从键盘输入当月利润I，求应发放奖金总数？
"""

def calcbonus(money):

    total = 0
    before = 0

    #各段利润奖金分配比例
    profit = [(100000, 0.1), (200000, 0.075), (400000, 0.05), (600000, 0.03), (1000000, 0.015)]

    if (0 >= money):

        print("The param(%s) is invalid!" % (str(money)))

        return -1

    for temp, pre in profit:

        if (money >= temp):

            total += (temp-before)*pre
            before = temp

        else:
            break

    total += (money - before) * pre

    return total

if __name__ == "__main__":

    while True:
        money = int(input("请输入当月总利润(元):"))

        result = calcbonus(money)

        if -1 != result:
            print("当月应发奖金为%.4f(元)"%(result))

尔东方

1. profit=int(input())
   
2. if profit<=100000:
   
3.         money=profit*0.1
   
4. elif 100000<=profit<=200000:
   
5.     money=100000*0.1+(profit-100000)*0.075
   
6. elif 200000<=profit<=400000:
   
7.     money=(profit-400000)*0.05+100000*0.1+(profit-100000)*0.075
   
8. elif 400000<=profit<=600000:
   
9.     money=(profit-400000)*0.03+(profit-400000)*0.05+100000*0.1+(profit-100000)*0.075
   
10. elif 600000<=profit<=1000000:
    
11.     money=(profit-600000)*0.015+(profit-400000)*0.03+(profit-400000)*0.05+100000*0.1+(profit-100000)*0.075
    
12. else:
    
13.     money=(profit-1000000)*0.01+(profit-600000)*0.015+(profit-400000)*0.03+(profit-400000)*0.05+100000*0.1+(profit-100000)*0.075
    
14. print(money)

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江少

1. while 1:
   
2.     number = raw_input('请输入一个数字：')
   
3.     n = int(number)
   
4.     if int(n) <= 100000:
   
5.         print n * 0.1
   
6.     elif 100000 < int(n) <= 200000:
   
7.         print (100000 * 0.1)+ (int(n)-100000)*0.075
   
8.     elif 200000 < int(n) <= 400000:
   
9.         print (100000*0.1+100000*0.075)+(int(n)-200000)*0.05
   
10.     elif 400000< int(n) <= 600000:
    
11.         print(100000*0.1+100000*0.075+200000*0.05)+(int(n)-400000)*0.03
    
12.     elif 600000< int(n) <= 1000000:
    
13.         print (100000*0.1+100000*0.075+200000*0.05+200000*0.03)+(int(n)-600000)*0.015
    
14.     elif int(n)>1000000:
    
15.          print(100000*0.1+100000*0.075+200000*0.05+200000*0.03+400000*0.015)+(int(n)-1000000)*0.01
    

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清风明月星

gopythoner 发表于 2017-3-31 23:54
虽然你的这个很看起来很简约，但是不符合一般的数学思维逻辑
在数学里面应该是这样：

在编程的时候，应该使用计算思维好一些，因为这样能发挥出计算机的优势，节省人的精力。

ForPorsche

1. I = float(input('输入当月利润:(单位：万):'))
   
2. award = 0
   
3. if I <= 10:
   
4.     award = 0.1 * I
   
5. elif I < 20:
   
6.     award = 0.1 * 10 + (I - 10)* 0.075
   
7. elif I < 40:
   
8.     award = 0.1 * 10 + 10 * 0.075 + (I - 20) * 0.05
   
9. elif I < 60:
   
10.     award = 0.1 * 10 + 10 * 0.075 + 20 * 0.05 + (I - 40) * 0.03
    
11. elif I < 100:
    
12.     award = 0.1 * 10 + 10 * 0.075 + 20 * 0.05 + 20 * 0.03 + (I - 60) * 0.015
    
13. else:
    
14.     award = 0.1 * 10 + 10 * 0.075 + 20 * 0.05 + 20 * 0.03 + 40 * 0.015 + (I - 100) * 0.01
    
15. print('应发奖金%.2f万' % award)

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鲨鱼辣椒1

def bonus():
    a = int(input("请输入利润:"))
    b = 100000 * 0.1     # 低于10W元部分
    c = 100000 * 0.075   # 10 - 20部分
    d = 100000 * 0.05
    e = 100000 * 0.03
    f = 100000 * 0.015

    if a <= 100000:
        h = a * 0.1
    elif 100000 < a < 200000:
        h = (a - 100000) * 0.075 + b
    elif 200000 < a < 400000:
        h = (a - 200000) * 0.05 + b + c
    elif 400000 < a < 600000:
        h = (a - 400000) * 0.03 + b + c + d
    elif 600000 < a < 1000000:
        h = (a - 600000) * 0.015 + b + c + d + e
    else:
        h = (a - 1000000) * 0.01 + b + c + d + e + f
    print("获得的奖金为:{}。".format(h))

while True:
    i = input("请问您要计算奖金吗?[YES/NO]:")
    if i == "YES":
        bonus()
    else:
        break

逃兵

1. I = int(input('当月利润I（万元）='))
   
2. if I<=10:
   
3.     bonus = 10*0.1
   
4. elif 10<I<=20:
   
5.     bonus = 10*0.1 + (I-10) * 0.075
   
6. elif 20<I<=40:
   
7.     bonus = 10*0.1 + (20-10) * 0.075+(I-20)*0.05
   
8. elif 40<I<=60:
   
9.     bonus = 10*0.1 + (20-10) * 0.075+(40-20)*0.05 + (I-40)*0.03
   
10. elif 60<I<=100:
    
11.     bonus = 10*0.1 + (20-10) * 0.075+(40-20)*0.05 + (60-40)*0.03 + (I-60)*0.015
    
12. else:
    
13.     bonus = 10*0.1 + (20-10) * 0.075+(40-20)*0.05 + (60-40)*0.03 + (100-60)*0.015 + (I-100) * 0.01
    
14. bonus = bonus*10000
    
15. print(bonus)
    

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逸野散人

有没有大佬会用递归写的
def MyMoney(num):
    num1 = 10 * 0.1
    num2 = 10 * 0.075
    num3 = 20 * 0.05
    num4 = 20 * 0.03
    num5 = 40 * 0.015
    if num <= 10:
        return  num*0.1
    elif 10 < num <= 20:
        return num1 + (num - 10)*0.075
    elif 20 < num <= 40:
        return num1 + num2 +(num - 20)*0.05
    elif 40 < num <= 60:
        return  num1 + num2 + num3 + (num - 40)*0.03
    elif 60 < num <= 100:
        return  num1 + num2 + num3 + num4 + (num - 60)*0.015
    elif 100 < num:
        return num1 + num2 + num3 + num4 + num5 + (num - 100)*0.01

salary = int(input("请输入利润（万元）："))
result = MyMoney(salary)
EndResult = result * 10000
print("今年的利润为：%d 万元"%salary,"\n","奖金应发放为：%d 元"%EndResult)

一块钱赫赫

all = int(input("请输入公司所得利润:"))
bene = [1000000,600000,400000,200000,100000]
rate = [0.01,0.015,0.03,0.05,0.075,0.1]
money = 0
for i in range(6):
    if all > bene[i]:
        money += (all - bene[i])*rate[i]
        money = bene[i]
        print(money)