Python：每日一题 78（答题领鱼币）

shen。

我想要看答案呢。嘻嘻

sunnychou

sunnychou

笨方法做了一下

1. def ave_num(s):#先把英文转阿拉伯数字求平均,求完以后，在转换回来逆运算
   
2.    
   
3.     a = dict(zip(('zero','one','two','three','four','five','six','seven','eight','nine'),range(0,10)))
   
4.     english = {
   
5.         0: 'zero',
   
6.         1: 'one',
   
7.         2: 'two',
   
8.         3: 'three',
   
9.         4: 'four',
   
10.         5: 'five',
    
11.         6: 'six',
    
12.         7: 'seven',
    
13.         8: 'eight',
    
14.         9: 'nine'
    
15.     }
    
16.     s = s.split(' ')
    
17.     sum = 0
    
18.     for i in s:
    
19.         if i not in a:
    
20.             return 'n/a'
    
21.         else:
    
22.             tmp=a.get(i,0)#radiansdict.get(key, default=None)：返回指定键的值，如果值不在字典中返回default值
    
23.             sum+=tmp
    
24.             #print(sum)
    
25.    
    
26.     return english.get(sum//len(s))
    
27.    
    
28. a = 'one two three'
    
29. print(ave_num(a))            

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2740710202

看看

好好学习P

学习大神！！！！！！！

hellolaynn

学习中

Araeh

看看大神

撒法空间

666

撒法空间

1. def average_string(s):
   
2.     L = ['zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine']
   
3.     num = 0
   
4.     newlist = s.split()
   
5.     for x in newlist:
   
6.         if x in L:
   
7.             num += L.index(x)
   
8.         else:
   
9.             return 'n/a'
   
10.     return num//len(newlist)

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guoxiaopeng

def average_string(s):
        m = {'zero':0,'one':1,'two':2,'three':3,'four':4,'five':5,'six':6,'seven':7,'eight':8,'nine':9}
        s2 = s.strip().split()
        suma = 0.0
        num = 0
        for item in s2:
                if item in m.keys():
                        suma = suma + m[item]
                        num+=1
                else:
                        print('n/a')
                        return
        print(suma/num)
原谅我是小白

我不爱杨幂

1

Greenland

1. def average_string(string):
   
2.     num = ['zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine']
   
3.     splited = string.split()
   
4.     if all(s in num for s in splited):
   
5.         return num[sum([num.index(s) for s in splited])//len(splited)] #平均数只保留整数部分
   
6.     else:
   
7.         return 'n / a'

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yangzhijian

厉害

ywhywh

def average_string(string):
    value = ['zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'ten']
    splitlist = string.split(' ')
    result = 0
    for english_num in splitlist:
        if english_num in value:
            result += value.index(english_num)
        else:
            return 'n / a'
    return value[int(result / len(splitlist))]
print(average_string('one three two'), average_string('five five five'), average_string('ku fthj two'), sep=' _(:3 」∠)_ ')

谁明浪子心l

ゞ泡沫ゞ

1

盼盼000011

学习一下！

solomonxian

平均数不是整数算超出范围吗？
输入错误和平均数非整数都算超出范围好了

踏实建个字典，逻辑非常清晰

1. def average_string(s):
   
2.     dic = dict(zip(("zero","one","two","three","four","five","six","seven","eight","nine"),range(10)))
   
3.     dic.update({v:k for k,v in dic.items()})
   
4.     try:
   
5.         return dic[sum(dic[i] for i in s.strip().split(" "))/len(s.strip().split(" "))]
   
6.     except KeyError:
   
7.         return 'n / a'

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不用字典看看，好像有点难看

1. def average_string2(s):
   
2.     letters = ("zero","one","two","three","four","five","six","seven","eight","nine")
   
3.     array = [letters.index(i) if i in letters else -1 for i in s.strip().split(" ")]
   
4.     return 'n / a' if (-1 in array) or sum(array)/len(array)%1 else letters[sum(array)//len(array)]

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冷笑寒风

啊阿啊阿啊阿啊阿

冷笑寒风

看看