Python：每日一题 78（答题领鱼币）

shen。

我想要看答案呢。嘻嘻

sunnychou

sunnychou

笨方法做了一下

def ave_num(s):#先把英文转阿拉伯数字求平均,求完以后，在转换回来逆运算
    
    a = dict(zip(('zero','one','two','three','four','five','six','seven','eight','nine'),range(0,10)))
    english = {
        0: 'zero',
        1: 'one',
        2: 'two',
        3: 'three',
        4: 'four',
        5: 'five',
        6: 'six',
        7: 'seven',
        8: 'eight',
        9: 'nine'
    }
    s = s.split(' ')
    sum = 0
    for i in s:
        if i not in a:
            return 'n/a'
        else:
            tmp=a.get(i,0)#radiansdict.get(key, default=None)：返回指定键的值，如果值不在字典中返回default值
            sum+=tmp
            #print(sum)
    
    return english.get(sum//len(s))
    
a = 'one two three'
print(ave_num(a))            

2740710202

看看

好好学习P

学习大神！！！！！！！

hellolaynn

学习中

Araeh

看看大神

撒法空间

666

撒法空间

def average_string(s):
    L = ['zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine']
    num = 0
    newlist = s.split()
    for x in newlist:
        if x in L:
            num += L.index(x)
        else:
            return 'n/a'
    return num//len(newlist)

guoxiaopeng

def average_string(s):
        m = {'zero':0,'one':1,'two':2,'three':3,'four':4,'five':5,'six':6,'seven':7,'eight':8,'nine':9}
        s2 = s.strip().split()
        suma = 0.0
        num = 0
        for item in s2:
                if item in m.keys():
                        suma = suma + m[item]
                        num+=1
                else:
                        print('n/a')
                        return
        print(suma/num)
原谅我是小白

我不爱杨幂

1

Greenland

def average_string(string):
    num = ['zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine']
    splited = string.split()
    if all(s in num for s in splited):
        return num[sum([num.index(s) for s in splited])//len(splited)] #平均数只保留整数部分
    else:
        return 'n / a'

yangzhijian

厉害

ywhywh

def average_string(string):
    value = ['zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'ten']
    splitlist = string.split(' ')
    result = 0
    for english_num in splitlist:
        if english_num in value:
            result += value.index(english_num)
        else:
            return 'n / a'
    return value[int(result / len(splitlist))]
print(average_string('one three two'), average_string('five five five'), average_string('ku fthj two'), sep=' _(:3 」∠)_ ')

谁明浪子心l

ゞ泡沫ゞ

1

盼盼000011

学习一下！

solomonxian

平均数不是整数算超出范围吗？
输入错误和平均数非整数都算超出范围好了

踏实建个字典，逻辑非常清晰

def average_string(s):
    dic = dict(zip(("zero","one","two","three","four","five","six","seven","eight","nine"),range(10)))
    dic.update({v:k for k,v in dic.items()})
    try:
        return dic[sum(dic[i] for i in s.strip().split(" "))/len(s.strip().split(" "))]
    except KeyError:
        return 'n / a'

不用字典看看，好像有点难看

def average_string2(s):
    letters = ("zero","one","two","three","four","five","six","seven","eight","nine")
    array = [letters.index(i) if i in letters else -1 for i in s.strip().split(" ")]
    return 'n / a' if (-1 in array) or sum(array)/len(array)%1 else letters[sum(array)//len(array)]

冷笑寒风

啊阿啊阿啊阿啊阿

冷笑寒风

看看